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29 Nov 2012, 09:50
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:38) correct
10%
(02:28)
wrong
based on 162
sessions
History
Date
Time
Result
Not Attempted Yet
Telephone Company X's monthly charge for long-distance telephone calls is $1.95 plus $0.10 per minute, whereas Telephone Company Y's monthly charge is $5.95 plus $0.08 per minute. For what total number of minutes of long-distance calls per month would the monthly charge for the two companies be the same?
A. 100
B. 120
C. 150
D. 180
E. 200
A. 100
B. 120
C. 150
D. 180
E. 200
06 Mar 2018, 09:15
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ritumaheshwari02
Let x = the total number of minutes of long-distance calls
Telephone Company X's monthly charge for long-distance telephone calls is $1.95 plus $0.10 per minute
So, TOTAL charge = $1.95 + $0.10(x)
Telephone Company Y's monthly charge is $5.95 plus $0.08 per minute
TOTAL charge = $5.95 + $0.08(x)
For what total number of minutes of long-distance calls per month would the monthly charge for the two companies be the same?
We want to satisfy the equation $1.95 + $0.10(x) = $5.95 + $0.08(x)
Subtract 1.95 from both sides to get: 0.1x = 4 + 0.08x
Subtract 0.08x from both sides to get: 0.02x = 4
So, x = 4/0.02
= 400/2
= 200
Answer: E
Cheers,
Brent
General Discussion
29 Nov 2012, 10:03
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ritumaheshwari02
For Company X : Charge = 1.95 + (0.10 *t)
For Company Y : Charge = 5.95 + (0.08*t)
where t is the time in minutes
Both the values will be equal
=> 1.95 + (0.10 *t) = 5.95 + (0.08*t)
=> 0.02 t = 4
=> t = 200
Answer will be E
Hope it helps!
