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Rock750
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Rock750
Two years ago, Sam put $1,000 into a savings account. At the end of the first year, his account had accrued $100 in interest bringing his total balance to $1,100. The next year, his account balance increased by 10%. At the end of the two years, by what percent has Sam's account balance increased from his initial deposit of $1,000 ?

A. 19%
B. 20%
C. 21%
D. 22%
E. 25%
Year 1 interest: $100
Year 2 interest, 10% of 1,100 = $110

Total interest = 100 + 110 = $210 (which equals the change in value)

\(\frac{change}{original}\) x 100 = percent change

\(\frac{210}{1000}\) = .21 x 100 = 21%

Answer C
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generis

Quote:
Two years ago, Sam put $1,000 into a savings account. At the end of the first year, his account had accrued $100 in interest bringing his total balance to $1,100. The next year, his account balance increased by 10%. At the end of the two years, by what percent has Sam's account balance increased from his initial deposit of $1,000 ?

A. 19%
B. 20%
C. 21%
D. 22%
E. 25%


Quote:
Year 1 interest: $100
Year 2 interest, 10% of 1,100 = $110


Total interest = 100 + 110 = $210 (which equals the change in value)

\(\frac{change}{original}\) x 100 = percent change

\(\frac{210}{1000}\) = .21 x 100 = 21%

Answer C

We are not given rate of interest (r) directly. Did you calculate the same by knowing principal amount (Rs.1000),
tenure (1 year), interest (Rs. 100) and using equation: Interest = PrT/100 for the first year and then using the same for the second year?

niks18
Is the highlighted part in question required to be given?
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generis
Quote:
Two years ago, Sam put $1,000 into a savings account. At the end of the first year, his account had accrued $100 in interest bringing his total balance to $1,100. The next year, his account balance increased by 10%. At the end of the two years, by what percent has Sam's account balance increased from his initial deposit of $1,000 ?

A. 19%
B. 20%
C. 21%
D. 22%
E. 25%
Quote:
Year 1 interest: $100
Year 2 interest, 10% of 1,100 = $110

Total interest = 100 + 110 = $210 (which equals the change in value)

\(\frac{change}{original}\) x 100 = percent change

\(\frac{210}{1000}\) = .21 x 100 = 21%

Answer C
We are not given rate of interest (r) directly. Did you calculate the same by knowing principal amount (Rs.1000),
tenure (1 year), interest (Rs. 100) and using equation: Interest = PrT/100 for the first year and then using the same for the second year?

niks18
Is the highlighted part in question required to be given?
adkikani , I think you ask two questions.

1) did I use simple interest rate equation?
2) why does it look as if I did?

No, I did not use interest rate
I used net change in money amount for each year

Year 1's change amount is given: + $100
Year 2's change rate is given:
10% increase on $1,100 = + $110

Then I calculated percent change from net amount change,
see original post. (Change/Original * 100)

Your question about the highlighted portion
is interesting.

If Sam left the earned interest in the bank;
and if Sam left the account alone;
of course we can calculate the amount in the account.
He put in $1000. He earned $100. His total = $1,100.

But we don't know what Sam did with the account.
The highlighted portion tells us that he left it alone.

• I suspect it appears that I used interest rates
because for any given first year,
if simple interest rate = annual compound interest rate,
amount yielded is identical.

Use interest rate? Yes, but . . .
If I were to calculate percent increase
using interest rates, I would:

1) not use strict SI (it's inaccurate)*
2) use multipliers or
3) use compound annual interest


For #2 and #3, I would omit principal amount. Not needed.

Percent change using
multipliers= compound interest rate


Multipliers - TOTAL factor increase

Multiplier, Year 1? Deduce from base + interest
\(1,000 + 100 = 1,100\)
Multiplier: \(\frac{1,100}{1,000}= 1.1\)

Multiplier for Year 2? Given.
10% increase on extant amount = \(1.1\)

Multipliers: TOTAL increase factor?
(Year 1 multiplier * Year 2 multiplier) = total increase factor
Total increase factor: \((1.1 * 1.1) = 1.21\)
Original base? \(1\)

Compound annual interest: TOTAL factor increase

\(A_{final}=P(1+.10)^{nt}\)
\(A_{final}=P(1.1)^{1*2}\)
\(A_{final}=P(1.1)^2\)
\(A_{final}=1.21P\)

\(A_{original}= P\)


Percent increase:

\(\frac{New-Old}{Old}*100\)

\((\frac{1.21-1}{1}*100)=(\frac{.21}{1}*100)\)
\(= .21*100=21\)
percent

OR \((\frac{1.21P-1P}{1P}*100)=(\frac{.21P}{1P}*100)\)
\(=.21*100=21\)
percent

Hope that answers your question.

*SI amount for both years?
INCORRECT if years are taken together
Run this formula for SI:
\(A_{final} = P(1 + rt)\)
Total after two years is $1,200. Not correct.

If you separate Year 1 and Year 2;
change \(P\) from $1,000 to $1,100;
and change \(t\) from 2 to 1;
SI formula will work.
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Given an initial deposit of $1,000, we must figure out the ending balance to calculate
the total percent change.
After the first year, Sam's account has increased by $100 to $1,100.
After the second year, Sam's account again increased by 10%, but we must take 10%
of $1,100, or $110. Thus the ending balance is $1,210 ($1,100 + $110).
To calculate the percent change, we first calculate the difference between the ending
balance and the initial balance: $1,210 – $1,000 = $210. We divide this difference by
the initial balance of $1,000 and we get $210/$1,000 = .21 = 21%.
The correct answer is C.
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Initial = $1000
Year 1: $1,100
Year 2: $1,100 × 1.1 = $1,210
Final ratio = $1,210/$1,000 = 1.21
Ratio increase = (final ratio - 1) = 0.21
Percentage increase:
= 0.21*100 = 21%

Answer: 21%
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