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i have a confusion in option D it is already given a and b is a nonnegative number
so using same method to solve option D as you used for solving option C
D would also be always negative Bunuel
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Bunuel
If a and b are nonzero integers, which of the following must be negative?

A. \((-a)^{-2b}=\frac{1}{(-a)^{2b}}=positive\).

B. \((-a)^{-3b}\) --> may be positive (consider a=1 and b=2) as well as negative (consider a=1 and b=1).

C. \(-(a^{-2b})=-\frac{1}{a^{2b}}=-\frac{1}{positive}=negative\)

D. \(-(a^{-3b})\) --> may be positive (consider a=-1 and b=1) as well as negative (consider a=1 and b=1).

E. None of these

Answer: C.


i have a confusion in option D it is already given a and b is a nonnegative number
so using same method to solve option D as you used for solving option C
D would also be always negative Bunuel

\(-(a^{-3b})=-\frac{1}{a^{3b}}\).

\(a^{3b}=a^{odd}\) can be negative as well as positive, while \(a^{2b}=a^{even}\) is always positive.
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i still don't understand, a^3b will always be positive because the question says a & b are not negative so ,so assuming a=1 b=1
a^3(1) will become positive and -(1/positive) will become negative as we cannot take take a=-1 or b=-1
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i still don't understand, a^3b will always be positive because the question says a & b are not negative so ,so assuming a=1 b=1
a^3(1) will become positive and -(1/positive) will become negative as we cannot take take a=-1 or b=-1

No, the question says "If a and b are nonzero integers, ", NOT non-negative.
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for option C consider a=-2 b=1
-(-2^-2*1)=-(-1/4) the answer would be +ve

Bunuel
If a and b are nonzero integers, which of the following must be negative?

A. \((-a)^{-2b}=\frac{1}{(-a)^{2b}}=positive\).

B. \((-a)^{-3b}\) --> may be positive (consider a=1 and b=2) as well as negative (consider a=1 and b=1).

C. \(-(a^{-2b})=-\frac{1}{a^{2b}}=-\frac{1}{positive}=negative\)

D. \(-(a^{-3b})\) --> may be positive (consider a=-1 and b=1) as well as negative (consider a=1 and b=1).

E. None of these

Answer: C.
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ahmedshehabb
for option C consider a=-2 b=1
-(-2^-2*1)=-(-1/4) the answer would be +ve

Bunuel
If a and b are nonzero integers, which of the following must be negative?

A. \((-a)^{-2b}=\frac{1}{(-a)^{2b}}=positive\).

B. \((-a)^{-3b}\) --> may be positive (consider a=1 and b=2) as well as negative (consider a=1 and b=1).

C. \(-(a^{-2b})=-\frac{1}{a^{2b}}=-\frac{1}{positive}=negative\)

D. \(-(a^{-3b})\) --> may be positive (consider a=-1 and b=1) as well as negative (consider a=1 and b=1).

E. None of these

Answer: C.

If a = -2, and b = 1, for C we get:

\(-(a^{-2b})= -((-2)^{-2*1}) = -((-2)^{-2}) = -(\frac{1}{(-2)^2}) = -(\frac{1}{4})=-\frac{1}{4}=negative\).
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