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555-605 (Medium)|   Algebra|      
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Revenge2013
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For any positive x, y and k, if kx is n% of y 23 Jul 2013, 15:19
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25% (medium)

Question Stats:

79% (01:38) correct 21% (02:08) wrong based on 413 sessions

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For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?

A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
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A
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For any positive x, y and k, if kx is n% of y 23 Jul 2013, 15:24
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Revenge2013
For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?

A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
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GIVEN
\(KX = (N/100)*Y\)

We have to find \((X/Y)*100\)

\(KX = (N/100)*Y\) ==> CLEARLY \((X/Y)*100 = N/K\) ...HENCE A
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For any positive x, y and k, if kx is n% of y 23 Jul 2013, 15:27
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Revenge2013
For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?

A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
Show more

kx is n% of y --> \(kx=y*\frac{n}{100}\) --> \(\frac{100x}{y}=\frac{n}{y}\).

What percentage must x be of y --> \(x=y*\frac{?}{100}\) --> \(?=\frac{100x}{y}\) --> \(?=\frac{n}{y}\).

Answer: A.
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For any positive x, y and k, if kx is n% of y 23 Jul 2013, 15:32
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blueseas
Revenge2013
For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?

A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
GIVEN
\(KX = (N/100)*Y\)

We have to find \((X/Y)*100\)

\(KX = (N/100)*Y\) ==> CLEARLY \((X/Y)*100 = N/K\) ...HENCE A
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Thanks a lot!

I got confused with the algebraic translation. Since "n% of y" is (n/100)y, I thought that "what percentage is x of y" would translate into (x/100)y rather than (x/y)100. :oops:

Guess I still have some work ahead of me...
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For any positive x, y and k, if kx is n% of y 23 Jul 2013, 23:37
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For any positive x, y and k, if kx is n% of y, then what percentage must x be of y?

A) (n/k)%
B) (n+k)%^n
C) (nk)%^n
D) (n-k)%
E) (100 (n/k))%
Show more

Plugging in is another method, which might avoid some confusion. Assume n = 100 %, thus kx = y, and \(\frac{x}{y}*100 = \frac{1}{k}*100 = \frac{n}{k} %\)

A.
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For any positive x, y and k, if kx is n% of y 11 Jan 2015, 17:08
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Hi All,

In these types of layered 'percent' questions, one or more of the wrong answers is usually what you would get to if you made a silly/little math mistake, so it's important to be rigorous with your work. In that same way, you can get to the correct answer by TESTing VALUES.

We're told that KX is N% of Y....

Let's TEST
Y = 100
N = 50

So KX = 50% of 100 = 50

K = 5
X = 10

The question then asks...what percentage must x be of y?
....what percentage must 10 be of 100?

10/100 = 10%

We're looking for an answer that = 10

A: N/K = 50/5 = 10 This IS a match.
B: (N+K)^N = 55^50 This is NOT a match
C: (NK)^N = 250^50 This is NOT a match
D: (N-K) = 50 - 5 = 45 This is NOT a match
E: 100(N/K) = 100(10) = 1000 This is NOT a match

Final Answer:
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A

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For any positive x, y and k, if kx is n% of y 15 Feb 2026, 02:55
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