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Updated on: 10 Jul 2019, 23:13
Originally posted by Asifpirlo on 20 Aug 2013, 12:47.
Last edited by Sajjad1994 on 10 Jul 2019, 23:13, edited 2 times in total.
Last edited by Sajjad1994 on 10 Jul 2019, 23:13, edited 2 times in total.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:32) correct
19%
(01:50)
wrong
based on 99
sessions
History
Date
Time
Result
Not Attempted Yet
If x < y < z, z = ky, x = 0, and the average of the numbers x, y, and z is 3 times the median, what is the value of k?
(A) –2
(B) 3
(C) 5.5
(D) 6
(E) 8
(A) –2
(B) 3
(C) 5.5
(D) 6
(E) 8
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
20 Aug 2013, 12:53
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Asifpirlo
Set in ascending order is {0, y, ky}
Median = y
Mean = 3y = (0 + y + ky)/3 --> 8y = ky --> since y > 0, then k = 8.
Answer: E.
20 Aug 2013, 12:58
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Asifpirlo
\(\frac{(X+Y+Z)}{3} = 3Y\)
and\(x=0\)
therefore \(z = 8y\)
also given\(z=ky\)
comparing \(K=8\)
HENCE E
