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Updated on: 10 Jul 2019, 23:16
Originally posted by Asifpirlo on 20 Aug 2013, 12:50.
Last edited by Sajjad1994 on 10 Jul 2019, 23:16, edited 2 times in total.
Last edited by Sajjad1994 on 10 Jul 2019, 23:16, edited 2 times in total.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
95% (00:53) correct
5%
(01:36)
wrong
based on 107
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A jar contains only three types of objects: red, blue, and silver paper clips. The probability of selecting a red paper clip is 1/4, and the probability of selecting a blue paper clip is 1/6. What is the probability of selecting a silver paper clip?
(A) 5/12
(B) 1/2
(C) 7/12
(D) 3/4
(E) 11/12
(A) 5/12
(B) 1/2
(C) 7/12
(D) 3/4
(E) 11/12
Source: Nova GMAT
Difficulty Level: 500
Difficulty Level: 500
20 Aug 2013, 12:56
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Asifpirlo
P(red)=1/4=3/12
P(blue)=1/6=2/12
P(silve)=1-(3/12+2/12)=7/12.
Answer: C.
20 Aug 2013, 13:12
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Hi,
i took LCM of both the denominator. LCM of both 4 and 6 is 24
if x/24=1/4 then x=6 similarly if y /24=1/6, then y=4
X+y =10 total=24,
Total no of silver= 24-10=14,
so the probability is .
14/24=7/12.
Hope my approach is correct bunnel pls comment
Posted from my mobile device
i took LCM of both the denominator. LCM of both 4 and 6 is 24
if x/24=1/4 then x=6 similarly if y /24=1/6, then y=4
X+y =10 total=24,
Total no of silver= 24-10=14,
so the probability is .
14/24=7/12.
Hope my approach is correct bunnel pls comment
Posted from my mobile device
