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jlgdr
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If k and w are the dimensions of a rectangle that has area.. 17 Sep 2013, 08:46
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C
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66% (01:17) correct 34% (01:15) wrong based on 410 sessions

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If k and w are the dimensions of a rectangle that has area 42, and if k and w are integers such that k > w, what is the total number of possible values of k?

(A) Two
(B) Three
(C) Four
(D) Five
(E) Six
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C
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If k and w are the dimensions of a rectangle that has area.. 17 Sep 2013, 08:49
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jlgdr
If k and w are the dimensions of a rectangle that has area 42, and if k and w are integers such that k > w, what is the total number of possible values of k?

(A) Two
(B) Three
(C) Four
(D) Five
(E) Six
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kw=42=42*1=21*2=14*3=7*6 --> k can take 4 values, namely: 7, 14, 21, and 42.

Answer: C.
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If k and w are the dimensions of a rectangle that has area.. 01 Mar 2015, 22:04
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Prime factorization

42=2*7*3

so, total number of distinct factors is (1+1)*(1+1)*(1+1)=8

k can have half of it, so 4

C
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If k and w are the dimensions of a rectangle that has area.. 01 Mar 2015, 23:43
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Following rectangles are possible:

1 42
2 21
3 14
6 7
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If k and w are the dimensions of a rectangle that has area.. 26 May 2017, 15:20
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k>w
both integers, we have the below situations:
w=1 => k=42
w=2 => k=21
w=3 => k=14
w=6 => k=7

other options will not be k>w - therefore, we have 4 options for k
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If k and w are the dimensions of a rectangle that has area.. 14 Jan 2018, 06:22
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as we know that k>w we need to find the factors of 42 that are true considering the given information:

42 =

42 x 1
21 x 2
14 x 3
7 x 6

So k could be 42, 21, 14 and 7

Answer is C
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If k and w are the dimensions of a rectangle that has area.. 14 Jan 2018, 08:55
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jlgdr
If k and w are the dimensions of a rectangle that has area 42, and if k and w are integers such that k > w, what is the total number of possible values of k?

(A) Two
(B) Three
(C) Four
(D) Five
(E) Six
Show more
Possible values are -
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Answer will be (B)
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If k and w are the dimensions of a rectangle that has area.. 07 Jun 2024, 04:03
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