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08 Oct 2013, 05:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:54) correct
19%
(02:37)
wrong
based on 334
sessions
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Jim begins a trip by driving for y hours at a constant speed of 65 miles per hour, and then slows to a constant speed of 55 miles per hour for the rest of the trip. What is the total distance Jim drives, in miles, if the trip takes x hours, and x > y?
\(a) \frac{65 + 55}{x-y}\)
\(b) \frac{65y + 55x}{x-y}\)
\(c) \frac{65}{y} + \frac{55}{x}\)
d) 65(y–x)+ 55(x–y)
\(e) 10y + 55x\)
\(a) \frac{65 + 55}{x-y}\)
\(b) \frac{65y + 55x}{x-y}\)
\(c) \frac{65}{y} + \frac{55}{x}\)
d) 65(y–x)+ 55(x–y)
\(e) 10y + 55x\)
08 Oct 2013, 06:13
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fozzzy
The distance covered at 65 miles per hour = (rate)*(time) = 65y miles.
The distance covered at 55 miles per hour = (rate)*(time) = 55(x-y) miles.
65y + 55(x-y) = 10y + 55x miles.
Answer: E.
General Discussion
09 Oct 2013, 20:35
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IMO E.
I actually solved this one using POE. It took me 10 seconds, but I would still prefer Bunuel approach
. Not sure if many ppl will like it but in case we are pressed for time, we could try this approach.
A. 65+55/(x-y) => (mi/hr) / hr will not give you distance in miles any how.
B. 65y+55x/(x-y) => (mi/hr) will not give you distance in miles
C. (65/y) + (55/x) => Same as A
Now we have only 2 options D & E. We already know that (x>y) , therefore y-x<0. This implies that 65(y-x)+55(x-y) <0 and distance can never be less than 0 as we consider it as an absolute quantity here.
Left is option E which looks reasonable and hence IMO E.
Hope this helps!!
I actually solved this one using POE. It took me 10 seconds, but I would still prefer Bunuel approach
. Not sure if many ppl will like it but in case we are pressed for time, we could try this approach.A. 65+55/(x-y) => (mi/hr) / hr will not give you distance in miles any how.
B. 65y+55x/(x-y) => (mi/hr) will not give you distance in miles
C. (65/y) + (55/x) => Same as A
Now we have only 2 options D & E. We already know that (x>y) , therefore y-x<0. This implies that 65(y-x)+55(x-y) <0 and distance can never be less than 0 as we consider it as an absolute quantity here.
Left is option E which looks reasonable and hence IMO E.
Hope this helps!!
