If candy bars that regularly sell for $0.40 each are on sale at two fo

Question

If candy bars that regularly sell for $0.40 each are on sale at two for $0.75, what is the percent reduction in the price of two such candy bars purchased at the sale price?

(A)  2\frac{1}{2}\%

(B)  6\frac{1}{4}\%

(C)  6\frac{2}{3}\%

(D)  8\%

(E)  12\frac{1}{2}\%

farful · Answer

Regular price is $0.80, sales price is $0.75.

So, 80-(80 * x%)=75
5 = 80*x%
x% = 5/80 = 1/16 = 6.25%

Funsho84 · Answer

you can use the percent change formula to answer this question: ((New - Old) / Old) *100

New = 75
Old = 80

((75-80)/ 80)*100 = 6.25
answer B

AkshdeepS · Answer

Regular price of two candies = 2 * 0.40 = $0.80

Discounted price of two candies =  $0.75

Difference =  0.85 - 0.75 = $0.5

Percent reduction at sale price =  \frac{0.5}{0.80}

= 6.25 %

(B)

Abhishek009 · Answer

\frac{80 - 75}{80}*100

=  6\frac{1}{4}% , Answer must be (B)

JeffTargetTestPrep · Answer

We use the formula for percent change: (new - old)/old x 100. The regular (old) price for two candy bars is 0.8, and the sale price (new) is 0.75;thus, the percent reduction is:

(0.75 - 0.8)/0.8 x 100

(75 - 80)/80 x 100

-5/80 x 100 = -1/16 x 100 = -100/16 = -25/4 = 6 1/4 percent less

Answer: B

reddymanohar2092 · Answer

2*0.40 =0.80
price given is 0.75

diff 0.05

(0.05/0.80)*100 = 25/4= 6 1/4

Thanks 
Manohar Reddy

ScottTargetTestPrep · Answer

The percent change is:

(0.75 - 0.8)/0.8 = -0.05/0.8 = -6.25%

Thus, the reduction is 6.25% or, equivalently, 6 1/4 %.

Answer: B

Hoozan · Answer

EducationAisle lets say we were asked to find the price reduction of 1. In that case we could still have found the percentage reduction of 2 and got our answer right? Whether we find the percentage reduction of 1,2 or 100 the answer will remain the same right?

Could you throw some light on this logic

Could you throw some light on this logic

EducationAisle · Answer

You are correct. Percentage reduction would still be the same, irrespective of the number of items that the sentence is talking about.

egmat · Answer

Here's how to think about this:

Step 1: Find the regular price for two candy bars

You know each candy bar normally costs  $0.40 . So if you're buying two at regular price:

Regular price for 2 bars =  2 	imes $0.40 = $0.80

This is your baseline—what you  would  pay without any sale.

Step 2: Identify the sale price for two candy bars

The problem tells you directly: two candy bars cost  $0.75  on sale.

Step 3: Calculate the dollar savings

How much are you actually saving?

Savings = Regular price − Sale price
Savings =  $0.80 - $0.75 = $0.05

You're saving 5 cents when you buy two candy bars on sale.

Step 4: Convert to percentage reduction

Here's the crucial formula for percent reduction:

Percent\ reduction = \frac{Amount\ saved}{Original\ price} 	imes 100\%

Notice that you  always  use the original price in the denominator, not the sale price.

Percent\ reduction = \frac{$0.05}{$0.80} 	imes 100\%

= \frac{5}{80} 	imes 100\%

= \frac{1}{16} 	imes 100\%

Now, to convert  \frac{1}{16}  to a percentage:

\frac{1}{16} = 0.0625 = 6.25\%

And  6.25\% = 6\frac{1}{4}\%

Answer: (B)  6\frac{1}{4}\%

The key insight here is understanding what quantity to compare and remembering that percent reduction always uses the  original  price as your base, not the new price.

Want to master the systematic approach?

You can check out the  step-by-step solution on Neuron by e-GMAT  to understand the complete framework for percent change problems and learn how to avoid the common traps that trip up most test-takers. You can also explore other GMAT official questions with detailed solutions on Neuron for structured practice  here .

Hope this helps! 😊

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