Last visit was: 24 Apr 2026, 03:03 It is currently 24 Apr 2026, 03:03
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
him1985
Joined: 20 Jan 2014
Last visit: 12 Jul 2018
Posts: 107
Own Kudos:
202
 [12]
Given Kudos: 120
Location: India
Concentration: Technology, Marketing
2
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
User avatar
manpreetsingh86
Joined: 13 Jun 2013
Last visit: 19 Dec 2022
Posts: 218
Own Kudos:
1,194
 [3]
Given Kudos: 14
Posts: 218
Kudos: 1,194
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
KrishnakumarKA1
Joined: 05 Jan 2017
Last visit: 13 Oct 2020
Posts: 398
Own Kudos:
314
 [1]
Given Kudos: 15
Location: India
Posts: 398
Kudos: 314
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,710
Kudos
Add Kudos
Bookmarks
Bookmark this Post
him1985
Consider a sequence of numbers given by the expression 7 + (n - 1) * 5, where n runs from 1 to 80.What is the sum of this series ?

A. 409
B. 1636
C. 16360
D. 16000
E. 15360

We are given the sequence 7 + (n - 1) * 5, in which n spans from 1 to 80. Let’s determine the first few values of the sequence.

n = 1

7 + (0 x 5) = 7

n = 2

7 + (1 x 5) = 12

n = 3

7 + (2 x 5) = 17

n = 4

7 + (3 x 5 ) = 22

We see that we have an evenly spaced set in which each term is 5 apart. To determine the sum, we can use the formula: sum = average x quantity. Since we know the quantity is 80, we need to determine the average.

We can use the formula: average = (first term in the set + last term in the set)/2

The last term in the set is 7 + (79 x 5) = 402, and thus:

average = (7 + 402)/2 = 409/2

Now we can calculate the sum:

sum = (409/2) x 80 = 16,360

Answer: C
User avatar
Nunuboy1994
Joined: 12 Nov 2016
Last visit: 24 Apr 2019
Posts: 554
Own Kudos:
Given Kudos: 167
Location: United States
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: Q157 V158
GPA: 2.66
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: Q157 V158
Posts: 554
Kudos: 126
Kudos
Add Kudos
Bookmarks
Bookmark this Post
manpreetsingh86
him1985
Consider a sequence of numbers given by the expression 7 + (n - 1) * 5, where n runs from 1 to 80.What is the sum of this series ?

A. 409
B. 1636
C. 16360
D. 16000
E. 15360

terms in this sequence are 7,12,17----402

now since this is an a.p. with a common difference of 5. therefore its sum can be given as
n(a+l)/2----------------1)

n= total no. of terms =80
a= first term=7
l= last term=402

subsitutuing values in the expression 1 we have

80(7+402)/2
= 40(409)
=16360

Kudos for the formula- I wanted to ask you- I see similar series problems on Veritasprep and wanted to ask if this formula is universal (I think it is). I have never seen this formula but now it makes a lot of sense- where did you get this formula from?
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,966
Own Kudos:
Posts: 38,966
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109802 posts
Tuck School Moderator
853 posts