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Hi All,

This question is really more about the 'thoroughness' of your thinking than anything else. Most Test Takers would look at this question and think "Oh, the answer is obviously X=1....", but is that really the ONLY answer???

The numbers -1, 0 and 1 have all sorts of interesting 'impacts' on how various math rules 'work', so it's important to keep them in mind as you work through the Quant section of the GMAT.

Here, we're asked what MUST be true based on the equation √x = x. You should be able to determine the 2 solutions to this equation (whether you do the formal algebra or not). Those solutions are 0 and 1. Using those answers as reference, only one of the 5 answers choices is correct...

Final Answer:

GMAT assassins aren't born, they're made,
Rich
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\(\sqrt{x}=x\)

\(\sqrt{x}^2=x^2\)

\(x = x^2\)

\(0 = \frac{x^2}{x}\)

\(0 =x\)

Nonnegative

D
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Thank you for the explanation,but i still have a question how is statement "A" and statement "D" differ in term of the meaning.
like statement "D" says x is a non negative number ,is it not same as "A" which says that x is a positive
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gagan543
Thank you for the explanation,but i still have a question how is statement "A" and statement "D" differ in term of the meaning.
like statement "D" says x is a non negative number ,is it not same as "A" which says that x is a positive

A. x is positive means \(x > 0\)

D. x is nonnegative means \(x \geq 0\)

As you can see option D allows x to be 0 too.
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amitabc
If \(\sqrt{x}=x\) , then which of the following must be true ?

A. \(x\) is positive
B. \(x = 1\)
C. \(x^2 > x\)
D. \(x\) is nonnegative
E. None of the above

An important Property is: The square root of something can't be negative

Thus, \(x\) mus be \(\ge 0\)

The answer is D.

Or,
\(\sqrt{x}^2\) = \(x^2\) Squaring both sides

\(x\) = \(x^2\)

\(x^2-x=0\)

\(x(x-1)=0\)

\(x=0\)

\(x-1=0\), \(x=1\)

So, \(x\) is non-negative.

The answer is D.
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