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\(Average =\) \(\frac{(Sum of Items)}{(Number of Items)}\)


It is given that average of first three tests is N i.e. \(\frac{Sum of First Three Tests}{3}\) \(=\) \(N\)
So Sum of First Three Tests\(= 3N\)

As per question, on his fourth test, he exceeds his previous average score by 20 points
i.e. he has scored \(N+ 20\) in fourth test .

So \(Average\) of 4 tests =\(\frac{(3N+ N+20)}{4}\) =\(N+5\)

Answer: C
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Answer = C) N + 5

Total of 1st 3 tests= 3N

4th test score = N + 20

Total of all 4 tests = 4N + 20

Average = N + 5
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Bunuel

Tough and Tricky questions: Number Properties.



On his first 3 tests, Rajeev received an average score of N points. If on his fourth test, he exceeds his previous average score by 20 points, what is his average score for his first 4 tests?

A) N
B) N + 4
C) N + 5
D) N + 10
E) N + 20

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Source: Chili Hot GMAT

Use plugging in to answer this question. Say he got a 60 on all of his first 3 tests to give him an average score of 60 points, so N=60. On his fourth test he would have scored 80 points. Using simple math we get the average to be 260/4. Simple calculations prove this to be 65, which is N + 5.
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Bunuel

Tough and Tricky questions: Number Properties.



On his first 3 tests, Rajeev received an average score of N points. If on his fourth test, he exceeds his previous average score by 20 points, what is his average score for his first 4 tests?

A) N
B) N + 4
C) N + 5
D) N + 10
E) N + 20


The sum of the first 3 test scores is 3N, and the 4th test score is N + 20, so the sum of all 4 test scores is:

3N + N + 20 = 4N + 20

So, his average score on the 4 tests is:

(4N + 20)/4 = N + 5

Answer: C
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Bunuel

Tough and Tricky questions: Number Properties.



On his first 3 tests, Rajeev received an average score of N points. If on his fourth test, he exceeds his previous average score by 20 points, what is his average score for his first 4 tests?

A) N
B) N + 4
C) N + 5
D) N + 10
E) N + 20


N=3

Average = N

New Total = N+20

New N=4

Average = N+5
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