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Updated on: 04 Dec 2014, 04:05
Originally posted by desaichinmay22 on 04 Dec 2014, 02:27.
Last edited by Bunuel on 04 Dec 2014, 04:05, edited 1 time in total.
Last edited by Bunuel on 04 Dec 2014, 04:05, edited 1 time in total.
Edited the question.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
67% (02:44) correct
33%
(03:14)
wrong
based on 455
sessions
History
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Time
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The ratio (p + q):(r + p):(q + r) = 3:4:10. (p + q + r) = 34. What is the value of q'
A) -6
B) 12
C) 18
D) 22
E) 40
A) -6
B) 12
C) 18
D) 22
E) 40
04 Dec 2014, 04:14
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desaichinmay22
\((p + q):(r + p):(q + r) = 3x:4x:10x\);
\((p + q) + (r + p) + (q + r) = 2(p + q + r) = 3x + 4x + 10x = 17x\);
Since \(p + q + r = 34\), then \(2*34 = 17x\) --> \(x = 4\).
\(p + q = 3x = 12\);
\(r + p = 4x = 16\);
\(q + r = 10x = 40\).
Solving above system gives \(q = 18\).
Answer: C.
Hope it's clear.
04 Dec 2014, 03:37
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Answer = C = 18
Lets say
p+q = 3 ........... (1)
r+p = 4 ............. (2)
q+r = 10 ........... (3)
Adding (1) (2) & (3)
2(p+q+r) = 17
\(p+q+r = \frac{17}{2}\)
However, given that p+q+r = 34
\(\frac{17}{2} * (How many times) = 34\)
Multiplication factor \(= 34 * \frac{2}{17} = 4\)
Start multiplying RHS of (1) (2) & (3) by 4
p + q = 12 ............ (4)
r + p = 16 ............. (5)
q + r = 40 .............. (6)
(4) - (5)
q - r = -4 ................ (7)
Adding (6) & (7)
2q = 36
q = 18
Lets say
p+q = 3 ........... (1)
r+p = 4 ............. (2)
q+r = 10 ........... (3)
Adding (1) (2) & (3)
2(p+q+r) = 17
\(p+q+r = \frac{17}{2}\)
However, given that p+q+r = 34
\(\frac{17}{2} * (How many times) = 34\)
Multiplication factor \(= 34 * \frac{2}{17} = 4\)
Start multiplying RHS of (1) (2) & (3) by 4
p + q = 12 ............ (4)
r + p = 16 ............. (5)
q + r = 40 .............. (6)
(4) - (5)
q - r = -4 ................ (7)
Adding (6) & (7)
2q = 36
q = 18
