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\(V* = V − \frac{V}{2}\)

\(V* = V (1 - \frac{1}{2})\)

\((V*)* = (V*) * \frac{1}{2}\)

\(3 = V * \frac{1}{2} * \frac{1}{2}\)

V = 3*2*2 = 12

Answer = A
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every V* is a half of correspondent V. We have two V*, final is 3, so 3*2=6 and 6*2=12

A
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Bunuel

Tough and Tricky questions: Functions.



For all real numbers V, the operation V* is defined by the equation V* =V − V/2 . If (V*)* = 3, then V =

A) 12
B) 6
C) 4
D) \(\sqrt{12}\)
E) −12

Kudos for a correct solution.

Source: Chili Hot GMAT
suppose V=1, the first operation results in 1-(1/2)=1/2; the second operation results in (1/2)-(1/4)= 1/4
If 1/4 is the final result, V=1
If 3 is the final result, V=12
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V*=3-----------(1)

Then
(V-V/2)* = (V-V/2)-((V-V/2)/2)
=((2v-v)/2) - ((2v-v)/4)
=(4v-2v-2v+v)/4--------(2)
From (1) and (2)
=>V/4=3
=>V=3x4=12

Now give me my "+1 Kudos" :P
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