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Answer = D

Radius of circle Z\(= \sqrt{6^2 + 8^2} = 10\)

Area of the semicircle \(= \frac{\pi10^2}{2} = 50\pi\)
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Bunuel

Tough and Tricky questions: Geometry.




If in the figure above, semicircles X and Y have radii of 6 and 8 feet, respectively, then what is the area of semicircle Z (in square feet)? (Note: Figure not drawn to scale.)

A. 10π
B. 20π
C. 25π
D. 50π
E. 100π


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Attachment:
2015-01-05_1756.png

OFFICIAL SOLUTION:

(D) If the radii of the semicircles X and Y are 6 feet and 8 feet, then their diameters are 12 and 16 feet. These diameters are both lengths of the legs of a right triangle, and the diameter of semicircle Z is the hypotenuse of this triangle.

The triangle is a 3-4-5 triangle, since the perpendicular legs are in the ratio 3 : 4. So the hypotenuse measures 20 feet, meaning the diameter of Z is 20 feet and its radius is 10 feet.

To determine the area of semicircle Z, we will determine the area of a full circle with the same radius as Z, and then divide this quantity by 2.The area of a circle with radius 10 is:
Area = πr²
Area = π10² = 100π.

Thus, the area of semicircle Z is 50π square feet.

The correct answer is choice (D).
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