pacifist85
Attachment:
chord.png
Circle J is centered on the origin. If the equation for a chord within that circle is x+(√3 )y=5 and that chord intersects the circle at the x-axis, what is the circumference of Circle J?
A 3π
B 5π
C 6π
D 8π
E 10π
I don't know whether the diagram is a part of the question or you have added it as a part of your attempt to solve the question.
If the diagram is a part of the question, then you can very easily see that radius is 5
Circumference = 2πr
Therefore circumference=2π * 5
Circumference =10π
Answer is E
IF the diagram is not a part of the circle then you can solve the question using the Cartesian pairs (x,y)
Since the chord intersect the circle at x axis , then it means its y coordinate is 0
substitute y=0 in the equation of chord x+(√3 )y=5
you will see that multiplying (√3 )y becomes√3 )*0 and the whole equation will become
x+0=5 ---> x=5 and the coordinate pair will become (5,0)
Now you can see that 5 is the radius
and again circumference is 2πr=2π5=10π
Answer is E again