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ske
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Hi ske,

While this question can be solved algebraically, it can also be solved with a bit of brute force and some Number Properties.

We're told that two numbers are in the ratio of 2:3. Thus, the two numbers could be...
2 and 3
4 and 6
6 and 9
8 and 12
10 and 15
Etc.

We're told that ADDING 4 to each number changes the ratio of the numbers to 5:7. We're asked for the DIFFERENCE between the original numbers.

Since adding 4 makes the first number a multiple of 5, this limits the possibilities....
2+4 = 6 NOT POSSIBLE
4+4 = 8 NOT POSSIBLE
6+4 = 10 This IS possible...Using this example, we would have...

"6 and 9", after adding 4 to each, becomes "10 and 13"...this is NOT a ratio of 5 to 7 though (even though it's pretty close), so we have to keep looking....

The next value that becomes a multiple of 5 when you add 4 to it is...16...
16 + 4 = 20

With "16 and 24", after adding 4 to each, we have "20 and 28." This IS a ratio of 5 to 7, so we have our pair of original numbers.

The difference between them is 8.

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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.


Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A 8

B 6

C 4

D 2

E 10




Let two numbers be a and b.

Since a:b=2:3, we have 2b=3a --> a=2k and b=3k.

So the difference of a and b is k(=3k-2k).

By the assumption in the question we have (2k+4):(3k+4) = 5:7.

That means 5*(3k+4)=7*(2k+4) ---> 15k+20=14k+28 ---> k=8.

The answer is, therefore, A.
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As after adding 4 numbers ratio becomes 5:7 so i checked for [5:7] * 2 or 3 or 4 so for 4, 20-4/28-4=16/24=2/3 so required numbers are 20 & 28 so difference is 8 option A
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Hi ramajha,

Your approach is also valid. When dealing with ratio questions on the GMAT, there are usually more ways than you might realize to get to the correct answer (some Tactical, some Algebraic, and some that are just 'brute force' arithmetic). Since no-one will ever know how you got the correct answer, you should use whatever approach you find to be fastest/easiest.

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ske
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A. 8
B. 6
C. 4
D. 2
E. 10
adding 4 numbers ratio becomes 5:7 so i checked for [5:7] * 2 or 3 or 4 so for 4, 20-4/28-4=16/24=2/3 so required numbers are 20 & 28 so difference is 8 option A
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ske
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A. 8
B. 6
C. 4
D. 2
E. 10
I solved similarly to Abhishek009 , with one different step.

\(\frac{2x + 4}{3x +\\
4}\) = \(\frac{5}{7}\). Cross multiply to get

14x + 28 = 15x + 20

x = 8, which is the multiplier for the original ratio

So original ratio is

\(\frac{(2)(8)}{(3)(8)}\) = \(\frac{16}{24}\) (Don't reduce - need original #s)

24 - 16 = 8

Answer A
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Let the no.s be 2x & 3x

so, 2x+4/3x+4= 5/7
14x+28=15x+20
x=8

difference= 3(8)-2(8)= 8 (Ans)
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