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Bunuel
Which of the following equations represents a line that is perpendicular to y=1/2*x+2?

A. y−2x=8
B. 2x+4y=10
C. 3y+6x=12
D. 4y−8x=16
E. 5x−10y=20

VERITAS PREP OFFICIAL SOLUTION:

In order for two lines to be perpendicular, the slopes need to be negative reciprocals of each other. Since the given slope is 1/2, you're looking for a slope of −2.

To find the slope, you need to put the equations in point-slope form, y = mx + b, where m is the slope. Checking the answer choices quickly:

Choices A, D, and E will each give x a positive coefficient, as your first step is to get y on the opposite side of the equation from x.

Only choice C simplifies to a coefficient of −2:

3y + 6x = 12

3y = −6x + 12

y = −2x + 4

So C is the correct answer.
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Bunuel
Which of the following equations represents a line that is perpendicular to y=1/2*x+2?

A. y−2x=8
B. 2x+4y=10
C. 3y+6x=12
D. 4y−8x=16
E. 5x−10y=20

Two lines are perpendicular when their slopes are negative reciprocal of each other.

Slope of given line =\(\frac{1}{2}\)

Required slope = \(-2\)

Only equation of line \(3y+6x=12\) satisfies

\(y = -2x + 12\)

(C)
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y = x/2 + 2
Slope , m = 1/2
Line perpendicular to respective line , their slope should be m= -2

A. y-2x =8
y = 2x-8 ; slope = 2 - Incorrect

B. 2x+4y = 10
4y=-2x+10 => 2y= -x+5 - Incorrect

C. 3y+6x=12
3y= -6x+12 => y= -2x+4 - Correct

D. 4y-8x=16
4y = 8x+16 - Incorrect

E. 5x-10y=20
-10y=-5x+20 - Incorrect

Please correct if I am wrong.
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