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Bunuel
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Hi All,

This question can be solved rather easily by TESTing VALUES (the approach that Abhishek009 used). The prompt never states that X and Y are positive though, so you don't have to use two different positive multiples of 5. You COULD use...

X = 0
Y = 5

That would make the calculations even easier/faster and still provide the correct answer to the question.

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Here we can choose 5,10 and 5,15 as the possible cases
and apart of E all satisfy the requirement
hence E
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