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03 Dec 2015, 06:28
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (02:07) correct
26%
(02:10)
wrong
based on 201
sessions
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A board of length L feet is cut into two pieces such that the length of piece A is 1 foot less than twice the length of piece B. Which of the following is the length, in feet, of piece A ?
A. (L - 1)/2
B. (2L + 1)/3
C. (L + 1)/3
D. (2L + 2)/3
E. (2L - 1)/3
A. (L - 1)/2
B. (2L + 1)/3
C. (L + 1)/3
D. (2L + 2)/3
E. (2L - 1)/3
03 Dec 2015, 06:35
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Let length of piece A and B be A feet and L-A feet
as per question
A=2(L-A)-1 => 3A=2L -1 => A=(2L-1)/3
as per question
A=2(L-A)-1 => 3A=2L -1 => A=(2L-1)/3
03 Dec 2015, 07:50
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Let length of piece A= 2x-1
length of piece B= x
2x-1+x = L
=>3x-1 = L
=>x = (L+1)/3
length of piece A=2[(L+1)/3] - 1
= (2L+2 -3)/3 = (2L-1)/3
Answer E
length of piece B= x
2x-1+x = L
=>3x-1 = L
=>x = (L+1)/3
length of piece A=2[(L+1)/3] - 1
= (2L+2 -3)/3 = (2L-1)/3
Answer E
