whitehalo wrote:

hi!

i don't understand the solutions given by CounterSniper and Skywalker18.

why is A= 2x-1 when B= x ?

shouldn't it be A= x-1 when B= x ?

No. You are not reading the statement properly.

The question is:

A board of length L feet is cut into two pieces such that the length of piece A is 1 foot less than twice the length of piece B. Which of the following is the length, in feet, of piece A ?

A. (L - 1)/2

B. (2L + 1)/3

C. (L + 1)/3

D. (2L + 2)/3

E. (2L - 1)/3If you look closely at the text in red above, you see that A is 1 foot less than TWICE the length of B. Thus, if B = x , then A = 2*B-1 = 2x-1.

Once you figure this out, you get L=x+2x-1=3x-1. ---> x=(L+1)/3 and A=2x-1 = 2(L+1)/3 -1 = (2L-1)/3. E is the correct answer.

Hope this helps.