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How many liters of water must be evaporated from 50 liters of a 3 percent sugar solution to get a 5 percent sugar solution?

A. 2
B. 4
C. 6
D. 10
E. 20

Sugar ----------------- solution ----------------%sugar
3/100*50=1.5----------50----------------------3
1.5-----------------------50-x---------------------5

1.5/(50-x) =5/100
x=20
Hence E.

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Bunuel
How many liters of water must be evaporated from 50 liters of a 3 percent sugar solution to get a 5 percent sugar solution?

A. 2
B. 4
C. 6
D. 10
E. 20

let x=liters of water to be evaporated
(.97*50)-x=.95(50-x)
x=20 liters
E
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Bunuel
How many liters of water must be evaporated from 50 liters of a 3 percent sugar solution to get a 5 percent sugar solution?

A. 2
B. 4
C. 6
D. 10
E. 20
Water is zero percent sugar
Let x = amount of water evaporated

Weighted average approach:

(% sugar)(Vol) - (% sugar)(Vol) = (% sugar)(Vol)

Below, you don't have to write 0(x) on LHS, obviously.

0(x) is there to highlight that we are subtracting \(x\) amount of evaporating water, and water is zero percent sugar -- such that volume of (50 - x) on RHS makes more intuitive sense.

\(.03(50) - 0(x) = .05(50 - x)\)
\(1.5 = 2.5 - .05x\)
\(.05x = 1\)
\(x =\frac{1}{.05}=\frac{100}{5}= 20\)


Answer E
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How many liters of water must be evaporated from 50 liters of a 3 percent sugar solution to get a 5 percent sugar solution?

The volume of water in 50 liters of a 3 percent sugar solution = 50*97% = 48.5 liter
The volume of sugar in 50 liters of a 3 percent sugar solution = 50*3% = 1.5 liter

On evaporation, the volume of water will decrease but the volume of sugar will be constant
For a 5 percent sugar solution, Let the total volume of the mixture be V
Therefore, [5V/100] = 1.5
=> V = 30 litre
The volume of water = 28.5

Volume of water evaporated = 48.5 - 28.5 = 20

Hence E
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Concentration 1 * Volume 1 = Concentration 2 * Volume 2
3% * 50 = 5% * V2
Volume final = 30

50 - 30 = 20 liters of water must be evaporated
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