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Bunuel please review the question, I think "[3][2/5] must have been mistakenly written. Because when I ignored 3, I got answer C) 4/19. Can you please clarify the issue? Thanks.
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Bunuel please review the question, I think "[3][2/5] must have been mistakenly written. Because when I ignored 3, I got answer C) 4/19. Can you please clarify the issue? Thanks.

_______________
Edited. Thank you.
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Hi All,

This question is essentially a 'lift' of an OG question.

In the GMAT2016: PS Question 175 (page 177).
In the GMAT2015/OG13: PS Question 151 (page 173).

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let 5 and 2=number of full time workers and trainees respectively
let 3 and 2= respective daily rates of each
(5)(3)=15 total daily full time worker envelopes stuffed
(2)(2)=4 total daily trainee envelopes stuffed
4/(4+15)=4/19=fraction of total daily envelopes stuffed by trainees
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Bunuel
At a local office, each trainee can stuff 2/3 as many envelopes per day as a full time worker. If there are \(\frac{2}{5}\) as many trainees as there are full time workers, then what fraction of all the envelopes stuffed in a day did the trainees stuff?

A. 2/19
B. 2/17
C. 4/19
D. 4/17
E. 14/15

Let 1 full time worker do x envelops
then 1 trainee = 2x/3

suppose there are 50 full time worker ...then they do 50x envelopes
then 20 trainee (2*50/5= 20) will do 20*2x/3 = 40x/3 envelops
together((envelops done by 20 trainees + envelops done by 50 full time workes)) they do 50x+ 40x/3 = 190x/3

required fraction = envelops done by 20 trainees / (envelops done by 20 trainees + envelops done by 50 full time workes)
40x/3 / 190x/3 == 4/19

Ans C
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1) Plug in easy numbers:
If #full time workers = 10, then #trainees 10*(2/5) = 4
If full time envelopes = 6, then trainee envelopes = 6*(2/3) = 4

2) Set up part/whole relationship: #trainees* t envelopes / #trainees * t envelopes + #full time *full time envelopes
16/(16+60) = 16/76 = 4/19
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Any advice to know how plug in the correct numbers?

Kind regards!
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gracie
let 5 and 2=number of full time workers and trainees respectively
let 3 and 2= respective daily rates of each
(5)(3)=15 total daily full time worker envelopes stuffed
(2)(2)=4 total daily trainee envelopes stuffed
4/(4+15)=4/19=fraction of total daily envelopes stuffed by trainees

Hello gracie

What am i doing wrong here?

150 (Total workers)

T = 60
E = 90

One hour per full time employee so:

40 hours of T and 90 hours for E.

40/130 = 4/13

I am confussed =/

Kind regards!
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Hi jfranciscocuencag,

This prompt is perfect for TESTing VALUES, but you have to carefully read the prompt and choose values based on the given information. We're told that "there are 2/5 as many trainees as there are full-time workers." Thus, the number of trainees is 2/5 of the other group; NOT 2/5 of the total of all employees.

For example: If we had 5 full-time workers, then we would have (2/5)(5) = 2 trainees.

Next, we're told that a trainee can stuff 2/3 as many envelopes in one day as a full-time worker.

For example: If a full-time worker can stuff 3 envelopes in one day, then a trainee can stuff (2/3)(3) = 2 envelopes in a day.

Using the values in these examples, can you finish off this question?

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Bunuel
At a local office, each trainee can stuff 2/3 as many envelopes per day as a full time worker. If there are \(\frac{2}{5}\) as many trainees as there are full time workers, then what fraction of all the envelopes stuffed in a day did the trainees stuff?

A. 2/19
B. 2/17
C. 4/19
D. 4/17
E. 14/15

If we let the number of full time workers = 10, then there are 2/5 x 10 = 4 trainees. If we let the number of envelopes each full time worker can stuff a day = 3 envelopes, then each trainee can stuff 2 envelopes per day.

Thus, in one day, the trainees stuffed (4 x 2)/(4 x 2 + 10 x 3) = 8/38 = 4/19 of the envelopes.

Answer: C
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Bunuel
At a local office, each trainee can stuff 2/3 as many envelopes per day as a full time worker. If there are \(\frac{2}{5}\) as many trainees as there are full time workers, then what fraction of all the envelopes stuffed in a day did the trainees stuff?

A. 2/19
B. 2/17
C. 4/19
D. 4/17
E. 14/15
Full time worker F , Trainee T
\(F*Rf*t=Wf\), where F total. full time workers, Rf rate of each worker, t is working time
\(2/5F*2/3Rf*t=Wt\)
So \(Wt/(Wf+Wt)\)
=\([(4/15)Wf]/[(4/15)Wf+Wf]\)
=(4/15)/19/15
=4/19
C:)
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Bunuel, I'd recommend putting 4/15 in the answer choices as it's an easy mistake to make (trainees envelopes / full-time envelopes)
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