TeymurHajiyev
In a certain group 50% of the students know English, 60% know French, 40% know German, and 10% do not know any of the languages. If 15% of the students know all three languages, what percent of the students know exactly two of the languages?
1) 15
2) 20
3) 30
4) 40
5) 50
I solved this question and have an answer, which is an OA, but still in doubt, because I've lost an answer list

Hi,
there is a direct formulae. wherein you can substitute the values to get the answer. but best would be to understand the concept...
let people who read Eng only= E..
let people who read French only= F..
let people who read German only= G..
let people who read Eng and German only= x..
let people who read Eng and French only= y..
let people who read French and German= z..
It is given that people who read all three = 15..
Now it is also given..
people who read Eng = E + x +y +15=50..
people who read French = F + x +z +15=60....
people who read German = G+ z +y +15=40...
add all three
E + x +y +15 + F + x +z +15 +G+ z +y + 15 = 50+60 +40=150..
3*15+ 2( x +y +z) + F +G+E= 150..
2( x +y +z) + F +G+E= 105 ....(i)
Also it is said that 10 do not read any so 90 read one or more..
we get 15+ x +y +z + F +G+E= 90..
x +y +z + F +G+E= 75.... substitute this value in (i)
so x+y+z + 75 =105..
x+y+z=30..
and this is nothing but all those who read only two newspapers
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