Last visit was: 22 Apr 2026, 22:05 It is currently 22 Apr 2026, 22:05
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
ninayeyen
Joined: 06 Apr 2010
Last visit: 31 May 2018
Posts: 13
Own Kudos:
Given Kudos: 7
Posts: 13
Kudos: 15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,765
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,765
Kudos: 810,695
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,765
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,765
Kudos: 810,695
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
ninayeyen
Joined: 06 Apr 2010
Last visit: 31 May 2018
Posts: 13
Own Kudos:
Given Kudos: 7
Posts: 13
Kudos: 15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
ninayeyen
If 5 z – 3 < 3 z + 4, which of the following cannot be a value of \(z^{3}\) ?

A) 0

B) 1

C) 8

D) 27

E) 6

5 z – 3 < 3 z + 4 gives z < 3.5. I think E should be 64, which is 4^4, in this case the answer would indeed be E.

Oh you are most likely right! pls can you break it down to how you got z? and why did you round up 3.5 to 4?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,765
Own Kudos:
Given Kudos: 105,850
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,765
Kudos: 810,695
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ninayeyen
Bunuel
ninayeyen
If 5 z – 3 < 3 z + 4, which of the following cannot be a value of \(z^{3}\) ?

A) 0

B) 1

C) 8

D) 27

E) 6

5 z – 3 < 3 z + 4 gives z < 3.5. I think E should be 64, which is 4^4, in this case the answer would indeed be E.

Oh you are most likely right! pls can you break it down to how you got z? and why did you round up 3.5 to 4?

5z – 3 < 3z + 4
5z - 3z < 4 + 3
2z < 7
z < 3.5

z must be 4 for z^3 to be 64. On the other hand z an be 0, 1, 2, or 3 thus z^3 can be 0, 1, 8, or 27.
User avatar
stne
Joined: 27 May 2012
Last visit: 22 Apr 2026
Posts: 1,808
Own Kudos:
Given Kudos: 678
Posts: 1,808
Kudos: 2,090
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If 5 z – 3 < 3 z + 4, which of the following cannot be a value of \(z^{3}\) ?

A) 0

B) 1

C) 8

D) 27

E) 6

5z – 3 < 3z + 4
5z - 3z < 4 + 3
2z < 7
z < 3.5

z must be 4 for z^3 to be 64. On the other hand z an be 0, 1, 2, or 3 thus z^3 can be 0, 1, 8, or 27.

Hi Bunuel ,
I was wondering the same thing, I was thinking no answer choice satisfies . Choose E because A to D at least gave Z as an integer and E did not . Then I scrolled down and understood everything . Wouldn't it better to change E from 6 to 64?
Thank you.
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,710
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ninayeyen
If 5 z – 3 < 3 z + 4, which of the following cannot be a value of \(z^{3}\) ?

A) 0

B) 1

C) 8

D) 27

E) 6

(Note: All the answer choices are perfect cubes except E, so we think it’s a typo. Choice E should be 64 instead of 6.)

5z - 3 < 3z + 4

2z < 7

z < 3.5

z^3 < 3.5^3

Since 64 = 4^3, it can’t be the value of z^3.

Alternate Solution:

If z^3 = 0, then z = 0. If z^3 = 1, then z = 1. If z^3 = 8, then z = 2. If z^3 = 27, then z = 3. The values z = 0, 1, 2 and 3 all satisfy the given inequality; therefore the answer must be E.

Answer: E
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 22 Apr 2026
Posts: 11,229
Own Kudos:
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,229
Kudos: 44,995
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ninayeyen
If 5 z – 3 < 3 z + 4, which of the following cannot be a value of \(z^{3}\) ?

A) 0

B) 1

C) 8

D) 27

E) 64


Hi..

The question has nothing to do with a perfect cube..
5z-3<3z+4........2z<7.......z<7/2
Therefore \(z^3<(\frac{7}{2})^3..........z^3<\frac{343}{8}...z<42.9\)

So z^3 can be anything LESS than 42.9. it can be even 41, need not be perfect cube.
It is not given that z is an integer

E
Moderators:
Math Expert
109765 posts
Tuck School Moderator
853 posts