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13 Apr 2016, 05:31
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
84% (01:15) correct
16%
(01:16)
wrong
based on 228
sessions
History
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If a, b, and c are consecutive integers such that a < b < c and a is an even prime number, which of the following is true?
I. a × b × c < a^3
II. a + b + c > a^3
III. 5b < bc
A. I only
B. II only
C. III only
D. II and III
E. I, II, and III
I. a × b × c < a^3
II. a + b + c > a^3
III. 5b < bc
A. I only
B. II only
C. III only
D. II and III
E. I, II, and III
13 Apr 2016, 07:04
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Only 'B' is possible solution. If a is even prime number i.e 2, b is 3 and c is 4
Putting the values in the answers only 'B' seems valid.
Putting the values in the answers only 'B' seems valid.
13 Apr 2016, 07:24
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Given:
1) a is even prime. The only even prime number known is 2, so a must be equal to 2.
2) a,b,c are consecutive such that a<b<c. So, b must be 3 and c must be 4.
So, we know that a=2, b=3 and c=4.
Substituting the above values in the three equations,
I. abc<a^3
which simplifies to 24<8. False.
II. a+b+c>a^3
which simplifies to 9>8. True.
III. 5b<bc
which simplifies to 15<12. False.
The only option correct is II, so the answer is B.
1) a is even prime. The only even prime number known is 2, so a must be equal to 2.
2) a,b,c are consecutive such that a<b<c. So, b must be 3 and c must be 4.
So, we know that a=2, b=3 and c=4.
Substituting the above values in the three equations,
I. abc<a^3
which simplifies to 24<8. False.
II. a+b+c>a^3
which simplifies to 9>8. True.
III. 5b<bc
which simplifies to 15<12. False.
The only option correct is II, so the answer is B.
