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Bunuel
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ameyaprabhu
is trial and error the only way to solve this, or is there a trick to eliminate the obvious ones?

Yes, you should do prime factorization to get the answer.
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Bunuel
Which of the following numbers has the greatest number of distinct prime factors?

A. 165
B. 192
C. 228
D. 330
E. 332

We can express each answer choice as a product of its prime factors:

A) 165

165 = 5 x 33 = 5 x 11 x 3

165 has 3 distinct prime factors.

B) 192

192 = 8 x 24 = 8 x 8 x 3 = 2^6 x 3^1

192 has 2 distinct prime factors.

C) 228

228 = 4 x 57 = 2^2 x 57

228 has 2 distinct prime factors.

D) 330

330 = 10 x 33 = 2 x 3 x 5 x 11

330 has 4 distinct prime factors.

E) 332

332 = 4 x 83 = 2^2 x 83

332 has 2 distinct prime factors.

330 has the greatest number of distinct prime factors.

Answer: D
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Bunuel
ameyaprabhu
is trial and error the only way to solve this, or is there a trick to eliminate the obvious ones?

Yes, you should do prime factorization to get the answer.

Bunuel mean there is no way out except applying factroization on every question it is taking time it took my 2 minutes :(
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Bunuel
Which of the following numbers has the greatest number of distinct prime factors?

A. 165
B. 192
C. 228
D. 330
E. 332

This requires us to find the prime factorization of each answer choice

A. 165 = (3)(5)(11) --- 3 distinct prime factors
B. 192 = (2)(2)(2)(2)(2)(2)(3) --- 2 distinct prime factors
C. 228 = (2)(2)(3)(19) --- 3 distinct prime factors
D. 330 = (2)(3)(5)(11) --- 4 distinct prime factors
E. 332 = (2)(2)(83) --- 2 distinct prime factors

Answer: D

Cheers,
Brent
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