Alex75PAris
Of the seminar classes at a certain university, 65% have 15 or fewer students and 95% have 10 or more students. If the same percentage of seminar contain 10,11,12,13,14 and 15 students, what is the median number of students per seminar ?
A. 12
B. 13
C. 14
D. 15
E. 15 or more
Check the diagram below:

As you can see 60% have 10, 11, 12, 13, 14, or 15 students. Since the same percentage of seminar contain 10, 11, 12, 13, 14 and 15 students, then 10% have 10 students, 10% have 11 students, 10% have 12 students, 10% have 13 students, 10% have 14 students, and 10% have 15 students.
To simplify, say that there are total of 100 seminars we'll have that:
5 have less than 10 students;
10 have 10 students;
10 have 11 students;
10 have 12 students;
10 have 13 students;
10 have 14 students;
10 have 15 students;
35 have more than 15 students.
The median of a set with even # of terms is the average of two middle terms (when ordered in ascending/descending order). Thus the median number of students per seminar will be the average of 50th and 51st seminars, when arranged in ascending order. 50th and 51st seminars, when arranged in ascending order, will have 14 students each (45 seminars will have less than 14 students, and seminars from 46th to 55th will have 14 students). The average is (14 + 14)/2 = 14.
Answer: C.
Hope it's clear.
Attachment:
Students.png [ 7.51 KiB | Viewed 2995 times ]