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26 May 2016, 12:23
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Difficulty:
45%
(medium)
Question Stats:
62% (01:39) correct
38%
(01:52)
wrong
based on 333
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Peter must choose a lab partner by picking a name out of a bag. If the bag has 9 male names and F female names, what is the least number of female names in the bag if the probability of choosing a male lab partner is less than 3 out of 7?
(A) 11
(B) 12
(C) 13
(D) 14
(E) 16
(A) 11
(B) 12
(C) 13
(D) 14
(E) 16
26 May 2016, 14:43
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Bunuel
Male Names in the bag = 9
Female Names in the bag = F
Probability of selecting a male name is = P = 9/(9+F)
The question asked is "what is the least number of female names in the bag if the probability of choosing a male lab partner is less than 3 out of 7?"
so, we need to find out the minimum value of F for which P<3/7
9/(9+F) < 3/7
Solving for F gives the equation;
F>12
Since the question asked is the minimum value F should be 13 ( F should be an integer).
28 May 2016, 08:44
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We know that we have 9 males and the probability that a male is chosen is 3/7. Multiply 3/7 by 3/3 and we get 9/21, we can then substract 9 from 21 and get 13
