Bunuel
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?
(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should
not use 3*3?
I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?
Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have
A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2
That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.
So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?
Someone, please answer this. even I had to read the question two times just to cross-check.
Although this question favors 6 and I completely get it why, but I think a slight word play in question can actually create 9 the right answer.
Would love to see how both the questions look like side by side.