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15 Jun 2016, 19:56
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
92% (01:42) correct
8%
(02:18)
wrong
based on 80
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A larger cube has 27 cubic inch as a volume and in the cube there are 27 smaller cubes such that their volume is 1 cubic inch. What is the difference between the surface areas’ sum of the 27 smaller cubes and the surface area of the larger cube, in square inch?
A. 54
B. 64
C. 81
D. 108
E. 120
*An answer will be posted in 2 days.
A. 54
B. 64
C. 81
D. 108
E. 120
*An answer will be posted in 2 days.
15 Jun 2016, 20:29
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Volume of larger cube = 27 = 3^3
Side of larger cube = 3
Volume of smaller cube = 1 --> Side of smaller cube = 1
Surface area of larger cube = 6 * 3^2 = 54
Surface area of 27 smaller cubes = 27 * 6 * 1 = 162
Difference = 162 - 54 = 108
Answer: D
Side of larger cube = 3
Volume of smaller cube = 1 --> Side of smaller cube = 1
Surface area of larger cube = 6 * 3^2 = 54
Surface area of 27 smaller cubes = 27 * 6 * 1 = 162
Difference = 162 - 54 = 108
Answer: D
17 Jun 2016, 02:08
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v=volume=a^3=27
therefore, a = 3= side of larger cube
SA larger cube = 6a^2 = 54
p=volume of smaller cube = 1 = z^3=1
therefore , z = 1 =side of the smaller cube
SA smaller cube = 6z^2 = 6
total = 27*6
difference = 27*6-54 = 27(6-2) = 27*4 = 108
therefore, a = 3= side of larger cube
SA larger cube = 6a^2 = 54
p=volume of smaller cube = 1 = z^3=1
therefore , z = 1 =side of the smaller cube
SA smaller cube = 6z^2 = 6
total = 27*6
difference = 27*6-54 = 27(6-2) = 27*4 = 108
