What is the sum of 60 consecutive integers from -29 inclusive, in a in

Question

What is the sum of 60 consecutive integers from -29 inclusive, in a increasing order?

A. -29
B. 29
C. -30
D. 30
E. 60

adiagr · Answer

From -29 to -1 --> 29 nos.
zero --> 1 number
from +1 to +29 --> 29 nos.

When we add up nos. from -29 to +29 sum will be zero. Total 59 nos will be added.

60th number will be "30".

Sum of these 60 nos. = 30.

D is the answer.

MathRevolution · Answer

(-29)+(-28)+…….+(-1)+0+1+…….+28+29+30=30. Hence, the correct answer is D.

shravan2025 · Answer

we can solve it by applying direct formula-
tn=a+(n-1)d
tn=-29+(60-1)1 
tn=+30 hence answer is D

mejia401 · Answer

30 numbers from -29 is +30, including -29 and 30 themselves. A, C are wrong because the number cannot be negative. B is not the answer since -29+29+1 is 59.
IMO D

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law258 · Answer

For this problem it is useful to try to visualize the number line:

-29 to 0:  how many numbers is that?  --> 29-0+1 = 30...GREAT! we're half way there

30-1+1 = 30 --> 30+30 = 60

We know that on the left hand side of zero we have -29 as the smallest value and on the right hand side we have all of the same values except 30. -29 cancels out with 29 in addition to all other values greater than -29 and less than 30. Thus, we are left with 30.

D is the correct answer.

ladyrenee95 · Answer

Number of Integers (inclusive) = N = (Last Number - First Number) +1

Sum of Integers = (First Number + Last Number)*N))/2

1.

We know N is 60 because it tells us that there are 60 integers and the smallest is -29, so -29 is the first number.

N =60 ... So 60 = (Last Number -(-29)) + 1

59 = Last Number - (-29)

59 + (-29) = 30 = Last Number

... So the range of numbers is between -29 to 30

2.  Sum of Integers = ((-29)+30))*60))/2 = 30  D

sghosh18 · Answer

Watching the symmetric pattern, and also including -29

we have -29 ....0 .... 29 both inclusive to be 59 numbers and its resultant sum comes out to be ZERO

So 60th number equal to the sum of the series = 30.

Alvarito · Answer

there is something i can not get or maybe i dont know yet

is "0" count as one number? because, -29 to -1 = 29 interger numbers, from 1 to 29 : another 29 integer numbers, so if we sum 29+29= 58 integer numbers, so we still have 2 interger numbers to count, these would be 30 and 31, and the result d'be 61 (there is no option for this answer) so my question is, is "0" count as number or integer?, because, that's the only way to be 59 integers, and the one left would be 30.

Bunuel · Answer

Yes, 0 is a number. What else it could be? ZERO: 1. 0 is an integer. 2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even. 3. 0 is neither positive nor negative integer (the only one of this kind). 4. 0 is divisible by EVERY integer except 0 itself. Check more here: https://gmatclub.com/forum/number-proper ... 74996.html

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What is the sum of 60 consecutive integers from -29 inclusive, in a in

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What is the sum of 60 consecutive integers from -29 inclusive, in a in

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