[quote="HarveyKlaus"]In the figure below, if AB=BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?
A) 24
B) 39
C) 51
D) 60
E) can't be determined
As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?
I appreciate your help.
Hi,
This is how I tried and I got it correct.
Given ABD is isosceles triangle i..e AB = BD i.e. angles BAD = BDA. ( for isosceles triangle two triangle will be equal and the third one will be different)
NOTE : The same two angles can be greater than or lesser than the third angle and this is the main point.Given angle BDC = 102 degrees.
Then remember one theorem that external side of triangle is sum of two interior angles.
i.e. 102 = angle B + angle A ---> eq 1.
Here angle A = angle D ( from isosceles triangle ABD)
We also know that sum of three angles in a triangle is 180 i.e. angle A + angle D + + angle B = 180 ( from isosceles triangle ABD).
i.e. two angles of A or D + angle B = 180 = > 2 A + B = 180. ( note A = D as they are same).
From options take B as 24 and sub in eq 1.
102 = angle B + angle A.
angle A = 102 - 24 = 78.
When angle A = 78 = angle D.Then sum of angles A + D + B = 78 + 78 + 24 = 180. I substituted the angles from options E to A but took 3 mins to solve.
Correct option is A.