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[quote="HarveyKlaus"]In the figure below, if AB=BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined

As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?

I appreciate your help.

Hi,

This is how I tried and I got it correct.

Given ABD is isosceles triangle i..e AB = BD i.e. angles BAD = BDA. ( for isosceles triangle two triangle will be equal and the third one will be different)

NOTE : The same two angles can be greater than or lesser than the third angle and this is the main point.

Given angle BDC = 102 degrees.

Then remember one theorem that external side of triangle is sum of two interior angles.

i.e. 102 = angle B + angle A ---> eq 1.

Here angle A = angle D ( from isosceles triangle ABD)

We also know that sum of three angles in a triangle is 180 i.e. angle A + angle D + + angle B = 180 ( from isosceles triangle ABD).

i.e. two angles of A or D + angle B = 180 = > 2 A + B = 180. ( note A = D as they are same).

From options take B as 24 and sub in eq 1.

102 = angle B + angle A.

angle A = 102 - 24 = 78.

When angle A = 78 = angle D.


Then sum of angles A + D + B = 78 + 78 + 24 = 180. I substituted the angles from options E to A but took 3 mins to solve.

Correct option is A.
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HarveyKlaus
In the figure below, if AB=BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined

As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?

I appreciate your help.

Hi,

This is how I tried and I got it correct.

Given ABD is isosceles triangle i..e AB = BD i.e. angles BAD = BDA. ( for isosceles triangle two triangle will be equal and the third one will be different)

NOTE : The same two angles can be greater than or lesser than the third angle and this is the main point.

Given angle BDC = 102 degrees.

Then remember one theorem that external side of triangle is sum of two interior angles.

i.e. 102 = angle B + angle A ---> eq 1.

Here angle A = angle D ( from isosceles triangle ABD)

We also know that sum of three angles in a triangle is 180 i.e. angle A + angle D + + angle B = 180 ( from isosceles triangle ABD).

i.e. two angles of A or D + angle B = 180 = > 2 A + B = 180. ( note A = D as they are same).

From options take B as 24 and sub in eq 1.

102 = angle B + angle A.

angle A = 102 - 24 = 78.

When angle A = 78 = angle D.


Then sum of angles A + D + B = 78 + 78 + 24 = 180. I substituted the angles from options E to A but took 3 mins to solve.

Correct option is A.
I think u need to frame question properly its AB=BC if AB=BD then sum of angles (triangle ABD)were > 180

Thanks
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HarveyKlaus
In the figure below, if AB=BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined

As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?

I appreciate your help.

Thanks


Hi!
Can I ask Bunuel to answer this question please? Would greatly appreciate!
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michaelkalend
HarveyKlaus
In the figure below, if AB=BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined

As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?

I appreciate your help.

Thanks

Hi!
Can I ask Bunuel to answer this question please? Would greatly appreciate!

In the figure below, if AB = BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined


Check below:


Angles ADB and CDB add up to 180°, thus (angle ADB) = 180° - (angle CDB) = 180° - 102° = 78°.

Since AB = BD, then ABD is an isosceles triangle and the angles at the base are equal. (angle ADB) = (angle DAB) = 78°.

All three angles in a triangle add up to 180°, thus (angle ADB) + (angle DAB) + (angle ABD) = 78° + 78° + (angle ABD) = 180°.

Solving gives (angle ABD) =24°.

Answer: A.

Hope it's clear.

Attachment:
Untitled2.png
Untitled2.png [ 3.74 KiB | Viewed 21496 times ]
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HarveyKlaus
In the figure below, if AB=BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined

As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?

I appreciate your help.

Thanks

Hi!
Can I ask Bunuel to answer this question please? Would greatly appreciate!

In the figure below, if AB = BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?

A) 24
B) 39
C) 51
D) 60
E) can't be determined


Check below:


Angles ADB and CDB add up to 180°, thus (angle ADB) = 180° - (angle CDB) = 180° - 102° = 78°.

Since AB = BD, then ABD is an isosceles triangle and the angles at the base are equal. (angle ADB) = (angle DAB) = 78°.

All three angles in a triangle add up to 180°, thus (angle ADB) + (angle DAB) + (angle ABD) = 78° + 78° + (angle ABD) = 180°.

Solving gives (angle ABD) =24°.

Answer: A.

Hope it's clear.

Attachment:
Untitled2.png


Very clear and became so much easy! Great! Thanks a lot!
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HarveyKlaus
In the figure below, if AB = BD and the measure of angle BDC is 102, what is the measure, in degrees, of the angle ABD?
Attachment:
Screen Shot 2016-07-10 at 11.54.42.png


A) 24
B) 39
C) 51
D) 60
E) can't be determined

∠BDC + ∠BDA = 180°

Or, 102° + ∠BDA = 180°

So, ∠BDA = 78°

Now, in ΔABD , ∠BDA = ∠BAD

So, we have ∠BAD + ∠BDA + ∠ABD = 180°

Or, 78° + 78° + ∠ABD = 180°

Or, ∠ABD = 24°

Thus, answer will be (A) 24°
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