HarveyKlaus wrote:
In the figure below, if AB=BD and the measure of angleBCD is 102, what is the measure, in degrees, of the angle ABD?
A) 24
B) 39
C) 51
D) 60
E) can't be determined
As we know that our triangle ABD is an isosceles triangle, so two angles are going to be equal. Now there are 2 options, either two of the angles are 78 degrees and the third one is 29 or one is 78 degrees and the other two are of 51. Im not sure how to to choose between these cases?
I appreciate your help.
Thanks
I hope its angle BDC=102Deg.
Anyway corrected fig. is given
Angle created by legs of isosceles triangle are equal
Here AB and AC are equal so angle related to them BAC and ACB are equal..
Coming to answer part
S0 angle BCA+BCD=180
BCA=72
AngleBCA=angle BAC=78Deg. (isosceles triangle)
Sum of angles of triangle=ABC=180
Angle ABC=24
Ans A
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