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Bunuel
Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $650. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $760. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear?

A. $2.50
B. $5.00
C. $5.50
D. $7.50
E. $15.00



Let X be pair of shoes and Y be pair of boots.

22x+16y = 650 ... eq1
8x +32y = 760....eq 2.

Now multiply eq 1 by 2 and sub eq 2.

44x = 1300
8x = 760.
- -
______________
36x = 540 => x = 15.

Sub x in eq 2.... we get 120 + 32y = 760... then we get 32y = 640 then y = 20

Differenece between X and Y is 5.

IMO option C is correct answer.

OA plesae...will correct if I missed anything.

The answer is indeed 5 but the option is B
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msk0657
Bunuel
Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $650. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $760. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear?

A. $2.50
B. $5.00
C. $5.50
D. $7.50
E. $15.00



Let X be pair of shoes and Y be pair of boots.

22x+16y = 650 ... eq1
8x +32y = 760....eq 2.

Now multiply eq 1 by 2 and sub eq 2.

44x = 1300
8x = 760.
- -
______________
36x = 540 => x = 15.

Sub x in eq 2.... we get 120 + 32y = 760... then we get 32y = 640 then y = 20

Differenece between X and Y is 5.

IMO option C is correct answer.

OA plesae...will correct if I missed anything.

The answer is indeed 5 but the option is B

Thanks..I edited the option...:)
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Bunuel
Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $650. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $760. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear?

A. $2.50
B. $5.00
C. $5.50
D. $7.50
E. $15.00

We can let h and b = the price per pair of shoes and boots, respectively, and create the equations:

22h + 16b = 650

11h + 8b = 325 (Eq. 1)

and

8h + 32b = 760

h + 4b = 95 (Eq. 2)

Multiplying Eq. 2 by -2 we have:

-2h - 8b = -190 (Eq. 3)

Adding Eq. 1 and Eq. 3 we have:

9h = 135

h = 15

Substituting h = 15 into Eq. 2 we have:

15 + 4b = 95

4b = 80

b = 20

Thus a pair of boots costs 20 - 15 = 5 dollars more than a pair of shoes.

Answer: B
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