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Bunuel
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The table below shows the enrollment in various classes at a certain 08 Aug 2016, 09:02
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73% (01:46) correct 27% (01:58) wrong based on 279 sessions

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The table below shows the enrollment in various classes at a certain college.

Class | Number of Students
Biology | 50
Physics | 35
Calculus | 40

Although no student is enrolled in all three classes, 15 are enrolled in both Biology and Physics, 10 are enrolled in both Biology and Calculus, and 12 are enrolled in both Physics and Calculus. How many different students are in the three classes?

A. 51
B. 88
C. 90
D. 125
E. 162
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B
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The table below shows the enrollment in various classes at a certain 08 Aug 2016, 10:20
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No. of total students = no of students of biology + no of students of physics but not biology + no of students of calculus but not biology and physics

No. of total students = 50 + (35-15) + (40-10-12) = 50+20+18 = 88

Hence, Answer will be B.
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The table below shows the enrollment in various classes at a certain 13 May 2019, 03:37
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To compare 3+ groups you can use the following formala:
Total = (Group 1) + (Group 2) + (Group 3) - (# of people who take 2 classes) - 2x(# of people who take all 3 classes) + (# who take neither)

Total = (50) + (35) + (40) - (15 + 10 + 12) - (none) - (none)
Total = 125 - 37
Total = 88
B
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The table below shows the enrollment in various classes at a certain 29 Jun 2020, 22:36
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Solution



Given

In a class,
    • 50 students opted for Biology
    • 35 students opted for Physics
    • 40 students opted for Calculus
    • 15 opted for both Biology and Physics.
    • 10 opted for both Biology and Calculus.
    • 12 Opted for both Physics and Calculus.
    • No one opted for all three.

To Find

    • Number of students in the class.

Approach and Working Out

    • The approach we can follow here is to count the number of total instances and then subtract the double or triple counting.
      o The total number of the count is just the sum of instances for each subject,
      o Double counting refers to the students who opted for two subjects.
      o Triple counting refers to the students who opted for three subjects.

    • Number of students = Count – Count of double subject – 2 x count of 3 subject
      o Double count needs to be removed once
      o Triple count needs to be removed twice.
    • Number of students = 50 + 35 + 40 – (15 + 12 + 10) – 2 x 0
        = 88

Correct Answer: Option B
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The table below shows the enrollment in various classes at a certain 25 Jul 2021, 09:25
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Bunuel
The table below shows the enrollment in various classes at a certain college.

Class | Number of Students
Biology | 50
Physics | 35
Calculus | 40

Although no student is enrolled in all three classes, 15 are enrolled in both Biology and Physics, 10 are enrolled in both Biology and Calculus, and 12 are enrolled in both Physics and Calculus. How many different students are in the three classes?

A. 51
B. 88
C. 90
D. 125
E. 162
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Just quick query : where does is say neither = 0 ? we know {group of three} = 0 . nothing about neither tho. just trying to understand if this is understood in these types of questions ?
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The table below shows the enrollment in various classes at a certain 01 Nov 2021, 12:18
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If we use the venn diagram approach and put the formula as X(EXACTLY ONE CLASS) + 2Y(EXACTLY 2 CLASSES) + 3Z(ALL THREE) = 125
i.e. X + 2x(10+15+12) + 3x0 = 125
X = 51
can someone please explain why this is wrong to use here ?
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The table below shows the enrollment in various classes at a certain 24 Apr 2023, 00:53
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