Last visit was: 25 Apr 2026, 22:31 It is currently 25 Apr 2026, 22:31
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
HarveyKlaus
Joined: 18 Feb 2015
Last visit: 13 May 2017
Posts: 69
Own Kudos:
666
 [10]
Given Kudos: 15
Posts: 69
Kudos: 666
 [10]
1
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
User avatar
Senthil1981
Joined: 23 Apr 2015
Last visit: 14 Oct 2021
Posts: 225
Own Kudos:
618
 [2]
Given Kudos: 36
Location: United States
Concentration: General Management, International Business
WE:Engineering (Consulting)
Posts: 225
Kudos: 618
 [2]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
abhimahna
User avatar
Board of Directors
Joined: 18 Jul 2015
Last visit: 06 Jul 2024
Posts: 3,481
Own Kudos:
Given Kudos: 346
Status:Emory Goizueta Alum
Products:
Expert
Expert reply
Posts: 3,481
Kudos: 5,779
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Senthil1981
Joined: 23 Apr 2015
Last visit: 14 Oct 2021
Posts: 225
Own Kudos:
Given Kudos: 36
Location: United States
Concentration: General Management, International Business
WE:Engineering (Consulting)
Posts: 225
Kudos: 618
Kudos
Add Kudos
Bookmarks
Bookmark this Post
abhimahna
Can you please help me understand how did you solve the abobe two highlighted equations? I want to know if there is any easy way to get the answer.


Hi Abhimahna,

I used onscreen calculator for taking twice the square root of (\(\sqrt{1.05}\)) and then solve for \(r\). Not aware of another approach.
Share if you come across.




+1 for kudos
User avatar
abhimahna
User avatar
Board of Directors
Joined: 18 Jul 2015
Last visit: 06 Jul 2024
Posts: 3,481
Own Kudos:
Given Kudos: 346
Status:Emory Goizueta Alum
Products:
Expert
Expert reply
Posts: 3,481
Kudos: 5,779
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Senthil1981
abhimahna
Can you please help me understand how did you solve the abobe two highlighted equations? I want to know if there is any easy way to get the answer.


Hi Abhimahna,

I used onscreen calculator for taking twice the square root of (\(\sqrt{1.05}\)) and then solve for \(r\). Not aware of another approach.
Share if you come across.




+1 for kudos

Sorry my friend. That is not the right approach to solve this question then.

Please note that this is a PS question and we are not going to get Onscreen calculator for the same. We need to ask/look for some other solution.

Experts, Please help!!
User avatar
Senthil1981
Joined: 23 Apr 2015
Last visit: 14 Oct 2021
Posts: 225
Own Kudos:
Given Kudos: 36
Location: United States
Concentration: General Management, International Business
WE:Engineering (Consulting)
Posts: 225
Kudos: 618
Kudos
Add Kudos
Bookmarks
Bookmark this Post
abhimahna


Sorry my friend. That is not the right approach to solve this question then.

Please note that this is a PS question and we are not going to get Onscreen calculator for the same. We need to ask/look for some other solution.

Experts, Please help!!


Thanks Abhimahna for pointing this. I'll look for another approach.
User avatar
Senthil1981
Joined: 23 Apr 2015
Last visit: 14 Oct 2021
Posts: 225
Own Kudos:
Given Kudos: 36
Location: United States
Concentration: General Management, International Business
WE:Engineering (Consulting)
Posts: 225
Kudos: 618
Kudos
Add Kudos
Bookmarks
Bookmark this Post
abhimahna

Can you please help me understand how did you solve the abobe two highlighted equations? I want to know if there is any easy way to get the answer.


I tried binomial theorem and applied to first power \((1 + x)^n = 1 + nx\) and it gave \(r\) as \(5%\) and closest to \(5%\) is \(4.91\).
User avatar
kannu44
Joined: 17 Aug 2012
Last visit: 22 Sep 2021
Posts: 83
Own Kudos:
74
 [2]
Given Kudos: 143
Location: India
Concentration: General Management, Strategy
GPA: 3.75
WE:Consulting (Energy)
Posts: 83
Kudos: 74
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I used approximation here . For simple interest , 5 % rate willl give interest of 1000$ on 20000$ . When it is compounded interest rate will be marginally lower .
User avatar
Shrija786
Joined: 18 May 2018
Last visit: 26 Nov 2018
Posts: 5
Own Kudos:
Given Kudos: 2
Posts: 5
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Senthil1981
HarveyKlaus
A college student expects to earn at least $1,000 in interest on an initial investment of $20,000. If the money is invested for one year at interest compounded quarterly, what is the least annual interest rate that would achieve the goal?

A) 4.91
B) 4.21
C) 5.72
D) 3.14
E) 1.08



Formula for Total if compounded quarterly is =\(P ( 1+ r/4 ) ^4\) for one year. Where r is in %.
So here, \(21,000 = 20,000 (1 + r/4)^4\)
= \(21/20 = 1.05 = (1 + r/4)^4\)
Then pick the median value from the choice (4.21 here) and substitute for r , make sure to convert from %
\((1+4.21/400)^4 < 1.05\)

If \(r = 4.91, (1+4.91/400)^4 = 1.05\). So 4.91 will give the minimum value for rate.
Answer is A







+1 for kudos


Can anybody please elucidate the problem again? Where did we get 21,000 from?
User avatar
pandeyashwin
Joined: 14 Jun 2018
Last visit: 25 Jan 2019
Posts: 165
Own Kudos:
Given Kudos: 176
Posts: 165
Kudos: 322
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Shrija786
Senthil1981
HarveyKlaus
A college student expects to earn at least $1,000 in interest on an initial investment of $20,000. If the money is invested for one year at interest compounded quarterly, what is the least annual interest rate that would achieve the goal?

A) 4.91
B) 4.21
C) 5.72
D) 3.14
E) 1.08



Formula for Total if compounded quarterly is =\(P ( 1+ r/4 ) ^4\) for one year. Where r is in %.
So here, \(21,000 = 20,000 (1 + r/4)^4\)
= \(21/20 = 1.05 = (1 + r/4)^4\)
Then pick the median value from the choice (4.21 here) and substitute for r , make sure to convert from %
\((1+4.21/400)^4 < 1.05\)

If \(r = 4.91, (1+4.91/400)^4 = 1.05\). So 4.91 will give the minimum value for rate.
Answer is A







+1 for kudos


Can anybody please elucidate the problem again? Where did we get 21,000 from?
Amount = Principal + Interest
21000 = 20000 + 1000
User avatar
Shrija786
Joined: 18 May 2018
Last visit: 26 Nov 2018
Posts: 5
Own Kudos:
Given Kudos: 2
Posts: 5
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can you please also explain the inequality sign?
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 25 Apr 2026
Posts: 5,986
Own Kudos:
Given Kudos: 163
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,986
Kudos: 5,859
Kudos
Add Kudos
Bookmarks
Bookmark this Post
HarveyKlaus
A college student expects to earn at least $1,000 in interest on an initial investment of $20,000. If the money is invested for one year at interest compounded quarterly, what is the least annual interest rate that would achieve the goal?

A) 4.91
B) 4.21
C) 5.72
D) 3.14
E) 1.08

Given:
1. A college student expects to earn at least $1,000 in interest on an initial investment of $20,000.
2. The money is invested for one year at interest compounded quarterly.

Asked: What is the least annual interest rate that would achieve the goal?

A college student expects to earn at least $1,000 in interest on an initial investment of $20,000.
Interest rate expected = $1000/$20000 = 5% annually
Let the annual interest rate that would achieve the goal of 5% annual interest rate be x%

The money is invested for one year at interest compounded quarterly.
\((1 + x/4)^4 - 1 > 5%\)
\((1+x/4)^4>1.05\)
If x=4.91%
\((1+x/4)^4 = 1.05001>1.05\)

IMO A
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,987
Own Kudos:
Posts: 38,987
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109830 posts
Tuck School Moderator
852 posts