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duahsolo
What is the remainder when the number 14^2 * 15^8 is divided by 5?

A) 0
B) 1
C) 2
D) 4
E) 5

14^2 * 15^8 = (some integer)*(a multiple of 5) = (a multiple of 5), hence the remainder upon division by 5 is 0.

Answer: A.
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We need to find the remainder when the number 14^2 * 15^8 is divided by 5

Theory
: Remainder of a number by 5 = Remainder of the units digit of the number by 5

Units digit of 14^2 * 15^8 = 6 * 5 (as units digit of any positive integer power of 5 is 5)
= Units digit of 30 = 0

=> Remainder of 14^2 * 15^8 by 5 = Remainder of 0 by 5 = 0

So, Answer will be A
Hope it helps!

MASTER Remainders by 2, 3, 5, 9, 10 and Binomial Theorem

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