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==> If you set A, and B sits on the left side of A, the rest can be seated with the number of cases of 4*3*2*1=24. If B sits on the right side of A, there can be 24 number of cases that they can be seated. Hence, 24+24=48. The answer is D.
Answer: D
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On six seating chairs including one red chair around a big round table , A, B, C, D, E, F each sit on a chair. A must sit on the red chair and B must be beside A. How many seating arrangement are?
A. 36 B. 40 C. 44 D. 48 E. 64

Attachment:
Seating.jpg
Seating.jpg [ 18.17 KiB | Viewed 2959 times ]
No of ways of Placing A = 1 ( Fixed )
No of ways of Placing B = 2 ( On either side of A )
No of ways of Placing C = 4
No of ways of Placing D = 3
No of ways of Placing E = 2
No of ways of Placing F = 1


So , Total number of ways is = No of ways of Placing A *No of ways of Placing B*No of ways of Placing C - F

Or, Total number of ways is = 1*2*4!

Or, Total number of ways is = 48

Hence answer will be (D) 48
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Hi Abhishek,

Why not (n-1)! for rest 4 people C to F?

-Abhijit
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Hi Abhishek,

Why not (n-1)! for rest 4 people C to F?

-Abhijit

For the rest of the 4 people, we are not taking (n-1)! because remember in a circular arrangement we fix the position of one person and arrange the rest using (n-1)! and in this question, we have already fixed the position of A. So, the remaining people would be arranged taking A as reference.

I hope it is clear now.
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