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19 Oct 2016, 08:17
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
79% (01:28) correct
21%
(02:09)
wrong
based on 683
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Train X is travelling at a constant speed of 30 miles per hour and Train Y is travelling at a constant speed of 40 miles per hour. If the two trains are travelling in the same direction along the same route but Train X is 25 miles ahead of Train Y, how many hours will it be until Train Y is 10 miles ahead of Train X?
A. 1.5
B. 2.0
C. 2.5
D. 3.0
E. 3.5
A. 1.5
B. 2.0
C. 2.5
D. 3.0
E. 3.5
03 Feb 2018, 16:38
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Manonamission
This is a "chase" question. One approach is the "gap" method.
The distance between Trains X and Y is the gap.
In "chase" problems (one traveler is behind another and needs to catch up), the relative rate, R used is (Faster - Slower)
Distance here?
Y is 25 miles behind X, and
Y needs to get 10 miles ahead of X
25 + 10 = 35 miles (= gap)
Relative rate (speed)?
Y is faster than X. Y catches and passes X.
Use relative speed (Faster - Slower) = (Y - X)
Rate = (40 mph - 30mph) = 10 mph = \(R\)
That's the rate (speed) at which the gap closes.*
Time required to cover that distance/close the gap?
\(R * T = D\), and \(T=\frac{D}{R}\)
\(Time = \frac{D}{R}=\frac{35mi}{10mph}=3.5\) hours
Answer E
*Y actually closes the gap. X and Y both move. Y moves faster. The rate at which Y closes the gap is Y's speed - X's speed.
19 Oct 2016, 08:26
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Train x is 25 miles ahead and we want to calculate the time by which Train y will be 10 miles ahead.
So total distance to be covered by Y is = 25+10 = 35 miles
Relative speed of Train y = 40-30 = 10 miles per hour (Relative speed concept)
Total time taken = Total Distance/Speed = 35/10 = 3.5 hrs.
Option E.
HTH
So total distance to be covered by Y is = 25+10 = 35 miles
Relative speed of Train y = 40-30 = 10 miles per hour (Relative speed concept)
Total time taken = Total Distance/Speed = 35/10 = 3.5 hrs.
Option E.
HTH
