Lets take 2 / 9 ..... One third of 9 is 3 .....and 2 is 1 less than 3 ..... So difference of the numerator ( 2 ) and one third of denominator ( 3 ) is 1 ..... Now .... Lets multiply both numerator and denominator with some numbers .....
( 2 × 2 ) / ( 9 × 2 ) = 4 / 18
( 2 × 3 ) / ( 9 × 3 ) = 6 / 27
Both 4 / 18 and 6 / 27 equals to 2 / 9 ..... But for 4 / 18 ..... Difference between numerator ( 4 ) and one third of denominator ( 6 ) is 2 ..... Which is double da difference of the numerator ( 2 ) and one third of denominator ( 3 ) in 2 / 9 .....
Again... For 6 / 27 .....difference of the numerator ( 6 ) and one third of denominator ( 9 ) is 3 ... Which is triple da difference of the numerator ( 2 ) and one third of denominator ( 3 ) in 2 / 9 .....
So now we know that multiplying both numerator and denominator of a fraction with same value will Automatically multiply da difference between numerator and one third of denominator......
Now.....lets try to make denominators of options da same.....
Lets.... ( 47 × 2 ) / ( 150 × 2 ) = 94 / 300 ..... So 94 is already 6 less than one third of 300 ......but 111 is only 5.67 less than one third of 350......so multiplying 47/ 150 anymore will only increase difference between numerator and one third of denominator......so 111 / 350 > 47 / 150
Now .... ( 111 × 2 ) / ( 350 × 2 ) = 222 / 700 ..... 222 is already 11.33 less than 233.33 which is one third of 700 ...... But 299 is only 1 less than one third of 900.... So multiplying 111 / 350 anymore will only increase difference between numerator and one third of denominator....... So 299 / 900 > 111 / 350 .....
So..... [ 47 / 150 ] < [ 111 / 350 ] < [ 299 / 900 ]