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Bunuel
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i have a concern with this question.
0 is the smallest multiple of every number.
Zero can't be a factor but it sure as hell is a multiple of every number.
I would like to see a zero in the options.
Or maybe add the word positive.
Else off course 154 is the answer (LCM)
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Bunuel
If x is divisible by 2, 14, and 11, which of the following must be the least multiple of x?

A. 308
B. 154
C. 70
D. 44
E. 20

No need to calculate LCM , from the given options check whether the option can be divided by 2 , 11 & 14..

One needs to go no further than (B) , hence that's our correct answer...
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Bunuel
If x is divisible by 2, 14, and 11, which of the following must be the least multiple of x?

A. 308
B. 154
C. 70
D. 44
E. 20

No need to calculate LCM , from the given options check whether the option can be divided by 2 , 11 & 14..

One needs to go no further than (B) , hence that's our correct answer...


What if Zero was in the options?
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stonecold
What if Zero was in the options?

The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.

Please revise the concept
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stonecold
What if Zero was in the options?

The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.

Please revise the concept


Actually thats Not My Question.
Here try this one => if-x-is-divisible-by-2-14-and-11-which-of-the-following-must-be-the-228248.html
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Bunuel
If x is divisible by 2, 14, and 11, which of the following must be the least multiple of x?

A. 308
B. 154
C. 70
D. 44
E. 20

We need to determine the LCM of 2, 14, and 11 or the LCM of 2^1, (7^1 x 2^1), and 11^1. To determine the LCM, we multiply the largest exponent of each unique prime factor.

Thus, the LCM is:

2^1 x 7^1 x 11^1 = 154

Answer: B
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Bunuel
If x is divisible by 2, 14, and 11, which of the following must be the least multiple of x?

A. 308
B. 154
C. 70
D. 44
E. 20

We need to determine the LCM of 2, 14, and 11 or the LCM of 2^1, (7^1 x 2^1), and 11^1. To determine the LCM, we multiply the largest exponent of each unique prime factor.

Thus, the LCM is:

2^1 x 7^1 x 11^1 = 154

Answer: B

Hi Jeff
Can you help me with this one.=> if-x-is-divisible-by-2-14-and-11-which-of-the-following-must-be-the-228248.html

Regards
Stone Cold
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