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14 Dec 2016, 05:55
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Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
64% (01:16) correct
36%
(01:15)
wrong
based on 229
sessions
History
Date
Time
Result
Not Attempted Yet
What is the greatest value of d such that 6^d is a factor of 18! ?
A. 3
B. 4
C. 5
D. 6
E. 8
A. 3
B. 4
C. 5
D. 6
E. 8
14 Dec 2016, 06:33
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\(6 = 2*3\)
18! has definitely more 2s than 3s, hence exponent of 3 will play determinant role in finding highest power of 6 in 18!.
\([\frac{18}{3}] + [\frac{18}{3^2}] = 6 + 2 = 8\)
Answer E
18! has definitely more 2s than 3s, hence exponent of 3 will play determinant role in finding highest power of 6 in 18!.
\([\frac{18}{3}] + [\frac{18}{3^2}] = 6 + 2 = 8\)
Answer E
General Discussion
14 Dec 2016, 08:11
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Bunuel
6 = 2 x 3
Highest part of 2 in 18! is 16
18/2 = 9
9/2 = 4
4/2 = 2
2/2 = 1
Highest part of 3 in 18! is 8
18/3 = 6
6/3 = 2
Since there are fewer 3's , correct answer will be there are 8 sixes...
Correct answer will be (E)
