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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
82% (01:02) correct
18%
(00:55)
wrong
based on 210
sessions
History
Date
Time
Result
Not Attempted Yet
Eight dogs are in a pen when a sled owner comes to choose two dogs to form a sled team. If the dogs are to be placed in a straight line and different orderings of the same dogs are considered the same team, how many different sled teams can the owner form?
A. 72
B. 56
C. 42
D. 30
E. 28
A. 72
B. 56
C. 42
D. 30
E. 28
07 Jan 2018, 10:29
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Bunuel
Since there are eight dogs in a pen and we need to choose 2 of these dogs to form a sled team,
there are \(C^2_8 = \frac{8!}{6!*2!} = \frac{8*7}{2} = 28\) ways to choose the teams(Option E)
09 Dec 2018, 16:03
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Hi Bunuel,
Is there a way to tell when a problem is going to be a C vs. a P? For instance, it seems in this problem that the words "different ordering" lead to the conclusion of C; however, sometimes I have trouble confidently determining this.
Your insight would be great. Thanks!
Is there a way to tell when a problem is going to be a C vs. a P? For instance, it seems in this problem that the words "different ordering" lead to the conclusion of C; however, sometimes I have trouble confidently determining this.
Your insight would be great. Thanks!
Bunuel
