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I don't think the above replies are wholly accurate... I don't think the smallest outlier value guarantees the smallest standard deviation?? Isn't it based on the entire data spread?

Standard deviation is the square root of the average of the squared differences between each set element and the set mean. Good luck calculating that in your head - I can't!

But by recognizing that the RANGE of Town C (maximum - minimum) is significantly less than the other towns and that the elements are fairly clustered around a central value of 160-ish, I was confident in intuiting that Town C would have the smallest standard deviation.

Is my logic correct or am I missing a hidden math rule of thumb here?
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AndyRugger, I believe your logic is correct, but rather than using intuition, it's better to check with formulae.

Since calculating the standard deviation is very time-consuming, before replying to the query, I personally solved it with both approaches.

Approximately Range=4 times SD, and using this relation, we can arrive at the conclusion that option C is correct.

Hope it helps
AndyRugger
I don't think the above replies are wholly accurate... I don't think the smallest outlier value guarantees the smallest standard deviation?? Isn't it based on the entire data spread?

Standard deviation is the square root of the average of the squared differences between each set element and the set mean. Good luck calculating that in your head - I can't!

But by recognizing that the RANGE of Town C (maximum - minimum) is significantly less than the other towns and that the elements are fairly clustered around a central value of 160-ish, I was confident in intuiting that Town C would have the smallest standard deviation.

Is my logic correct or am I missing a hidden math rule of thumb here?
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AbhishekP220108
AndyRugger, I believe your logic is correct, but rather than using intuition, it's better to check with formulae.

Since calculating the standard deviation is very time-consuming, before replying to the query, I personally solved it with both approaches.

Approximately Range=4 times SD, and using this relation, we can arrive at the conclusion that option C is correct.

Hope it helps

I appreciate the insight! I believe, however, that the Range/4 = approx. Standard Deviation is based on the normal distribution curve, which isn't a wholly accurate assumption with these sample sets. It'll get you close, though. In this case, the range was different enough that the rule of thumb worked, but it's only an approximation for real data sets, not an equality.
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