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Bunuel
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√21/6, can be written as √21/(√4 * √9)

=> Cancelling out √3 from numerator and denominator, we get √7/(√4 * √3)

=> Above can be written as √7/√12

Therefore, Answer is C
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JeffTargetTestPrep
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Which of the following is equivalent to \(\frac{\sqrt{21}}{6}\)?

A. \(\frac{\sqrt{7}}{2}\)

B. \(\sqrt{\frac{7}{2}}\)

C. \(\sqrt{\frac{7}{12}}\)

D. \(\frac{7}{\sqrt{6}}\)

E. \(\frac{21\sqrt{6}}{6}\)

Let’s simplify the given expression:

√(21)/6 = √(21)/√(36) = √(21/36) = √(7/12)

Answer: C

why you took denominator in root any particular reason
TIA
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ehsan090
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Bunuel
Which of the following is equivalent to \(\frac{\sqrt{21}}{6}\)?

A. \(\frac{\sqrt{7}}{2}\)

B. \(\sqrt{\frac{7}{2}}\)

C. \(\sqrt{\frac{7}{12}}\)

D. \(\frac{7}{\sqrt{6}}\)

E. \(\frac{21\sqrt{6}}{6}\)

Let’s simplify the given expression:

√(21)/6 = √(21)/√(36) = √(21/36) = √(7/12)

Answer: C

why you took denominator in root any particular reason
TIA


because you have to reduce the expresson
and we can reduce by cancelling factor 3 which is present in both num. & denominator :)
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Bunuel
Which of the following is equivalent to \(\frac{\sqrt{21}}{6}\)?

A. \(\frac{\sqrt{7}}{2}\)

B. \(\sqrt{\frac{7}{2}}\)

C. \(\sqrt{\frac{7}{12}}\)

D. \(\frac{7}{\sqrt{6}}\)

E. \(\frac{21\sqrt{6}}{6}\)

Square both Numerator and Denominator : \(\frac{21}{36}\) => \(\frac{7}{12}\)

Since, we have taken square both in numerator and denominator, the actual value of the fraction will be : \(\sqrt{\frac{7}{12}}\)

Hence, answer must be (C) \(\sqrt{\frac{7}{12}}\)
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[/quote]

why you took denominator in root any particular reason
TIA[/quote]


because you have to reduce the expresson
and we can reduce by cancelling factor 3 which is present in both num. & denominator :)[/quote]

Thanks mate a little clear. I need to practice these type of question for more clear understanding
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√21/6
=√3*√7/3*2
=√7/√3*√4 as √4=2
=√7/√12
=√(7/12) Hence, Answer is C
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sqrt (21) / 6 is less than 1

The only option in the answer choices that is less than 1 is C.

Hope this helps
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