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A restaurant is hanging 7 large tiles on its wall in a single row 17 Feb 2017, 16:37
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Question Stats:

77% (01:07) correct 23% (01:47) wrong based on 244 sessions

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A restaurant is hanging 7 large tiles on its wall in a single row. How many arrangements of tiles are possible if there are 3 white tiles and 4 blue tiles?

A. 35
B. 12
C. 21
D. 84
E. 28
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A restaurant is hanging 7 large tiles on its wall in a single row 17 Feb 2017, 19:40
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vikasp99
A restaurant is hanging 7 large tiles on its wall in a single row. How many arrangements of tiles are possible if there are 3 white tiles and 4 blue tiles?

A. 35
B. 12
C. 21
D. 84
E. 28
Show more


Hi..

Total ways these 7 tiles can be arranged =7!
However these contain duplicity as 3 tiles are of one colour and other 4 are of other colour..
So eliminating these = \(\frac{7!}{3!4!}\)=35

A
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A restaurant is hanging 7 large tiles on its wall in a single row 20 Jan 2019, 08:21
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vikasp99
A restaurant is hanging 7 large tiles on its wall in a single row. How many arrangements of tiles are possible if there are 3 white tiles and 4 blue tiles?

A. 35
B. 12
C. 21
D. 84
E. 28
Show more


Hello Bunuel,

Isn't this question confusing. 3 White tiles could be different white tiles and/or 4 blue tiles could be different blue tiles ? How we can make sure that all white/blue tiles are similar ?

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Amm
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A restaurant is hanging 7 large tiles on its wall in a single row 20 Jan 2019, 17:59
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I understand your attention to detail (based on some convoluted and tricky gmat questions), but it I have not found it necessary for combination questions. Most people (including and especially me) find this section confusing. The questions ask straight forward questions and simply require application of rules. This question tests 'permutation with repeated elements'.

\(P(n; n_1, n_2, . . . , n_k) = \frac{n!}{n_1! n_2! . . . n_k!}\)
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A restaurant is hanging 7 large tiles on its wall in a single row 09 Apr 2024, 02:13
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chetan2u

vikasp99
A restaurant is hanging 7 large tiles on its wall in a single row. How many arrangements of tiles are possible if there are 3 white tiles and 4 blue tiles?

A. 35
B. 12
C. 21
D. 84
E. 28

Hi..

Total ways these 7 tiles can be arranged =7!
However these contain duplicity as 3 tiles are of one colour and other 4 are of other colour..
So eliminating these = \(\frac{7!}{3!4!}\)=35

 
Show more
­Hi there, isn't it a combination problem, as the question stem doesn't express any nessacity of following certain order?
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A restaurant is hanging 7 large tiles on its wall in a single row 09 Apr 2024, 02:32
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chetan2u

vikasp99
A restaurant is hanging 7 large tiles on its wall in a single row. How many arrangements of tiles are possible if there are 3 white tiles and 4 blue tiles?

A. 35
B. 12
C. 21
D. 84
E. 28

Hi..

Total ways these 7 tiles can be arranged =7!
However these contain duplicity as 3 tiles are of one colour and other 4 are of other colour..
So eliminating these = \(\frac{7!}{3!4!}\)=35

 
­Hi there, isn't it a combination problem, as the question stem doesn't express any nessacity of following certain order?
Show more

Hi

The word arrangements tells you that order matters. If it were selection we would be looking at combination

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A restaurant is hanging 7 large tiles on its wall in a single row 09 Apr 2024, 02:36
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ShuvoDhk

chetan2u

vikasp99
A restaurant is hanging 7 large tiles on its wall in a single row. How many arrangements of tiles are possible if there are 3 white tiles and 4 blue tiles?

A. 35
B. 12
C. 21
D. 84
E. 28
Hi..

Total ways these 7 tiles can be arranged =7!
However these contain duplicity as 3 tiles are of one colour and other 4 are of other colour..
So eliminating these = \(\frac{7!}{3!4!}\)=35



 
­Hi there, isn't it a combination problem, as the question stem doesn't express any nessacity of following certain order?
Show more
­Can you please clarify what you mean by "it's a combination problem"? What, according to you, should the answer be?

P.S. The wording would have been better if the question mentioned that 3 white tiles are identical and 4 blue tiles are also identical. If they are not, then the answer would simply be 7!.­
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