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Given that ∆ x = x for x ≥ 0 and 2x for x < 0 and we need to find the value of \(\frac{∆30}{∆(-5)}\)

∆30 = 30 (because ∆ x = x for x ≥ 0)
∆(-5) = 2*-5 = -10 (because ∆ x = 2x fo)

=> \(\frac{∆30}{∆(-5)}\) = \(\frac{30}{-10}\) = -3

So, Answer will be C
Hope it helps!

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