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Bunuel
What is \(2^6 + 2^6 + 3^6 + 3^6 + 3^6\)?

A. 2^12 + 3^18
B. 4^6 + 9^9
C. 4^12 + 9^18
D. 2^7 + 3^7
E. 13^6

2^6 + 2^6 + 3^6 + 3^6 + 3^6 = 2^6(1 + 1) + 3^6(1 + 1 + 1) = 2^6(2^1) + 3^6(3^1) = 2^7 + 3^7
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\(2^6(1+1)\) + \(3^6(1+1+1)\)
\(2^6(2) + 3^6(3)\)
\(2^7 + 3^7\) - Answer D
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=>2^6+2^6+3^6+3^6+3^6
=>2^6(1+1) + 3^6(1+1+1)
=>2^6*2 + 3^6 * 3
=> 2^7 + 3^7


SMASH THAT D.
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Bunuel
What is \(2^6 + 2^6 + 3^6 + 3^6 + 3^6\)?

A. 2^12 + 3^18
B. 4^6 + 9^9
C. 4^12 + 9^18
D. 2^7 + 3^7
E. 13^6

Pay close attention to the pattern

2^6 + 2^6 = 2(2)^6 =2^7
3^6 + 3^6 +3^6 = 3(3)^6 = 3^ 7 - same thing

2^7 +3^7

Thus
"D"
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Bunuel
What is \(2^6 + 2^6 + 3^6 + 3^6 + 3^6\)?

A. 2^12 + 3^18
B. 4^6 + 9^9
C. 4^12 + 9^18
D. 2^7 + 3^7
E. 13^6

\(2^6 + 2^6 + 3^6 + 3^6 + 3^6\)

Or, \(2^6 ( 1 + 1 ) + 3^6 (1 + 1 + 1 )\)

Or, \(2^6 ( 2 ) + 3^6 (3 )\)

Or, \(2^7 + 3^7\)

Hence, answer will be (D)
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