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26 Apr 2017, 08:16
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
87% (01:38) correct
13%
(01:56)
wrong
based on 297
sessions
History
Date
Time
Result
Not Attempted Yet
Teneka and Francis leave Town A at 9:00 a.m. driving north along Highway B, in seperate cars. Teneka drives 30 miles per hour and Francis drives 40 miles per hour. If after traveling 240 miles Francis' car breaks down and stops, at what time will Teneka's car reach Francis' car?
A. 11 p.m.
B. 10 p.m.
C. 6 p.m.
D. 5 p.m.
E. 3 p.m.
A. 11 p.m.
B. 10 p.m.
C. 6 p.m.
D. 5 p.m.
E. 3 p.m.
03 Apr 2018, 09:51
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Bunuel
Given: Francis drives 240 miles and then stops (breaks down)
So, Teneka will reach Francis once Teneka drives 240 miles.
How long will it take Teneka to drive 240 miles?
Time = distance/speed = (240 miles)/(30 miles per hour) = 8 hours
Teneka started driving at 9:00am
So, after 8 hours, the time will be 5pm
Answer: D
Cheers,
Brent
General Discussion
26 Apr 2017, 10:25
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Hopefully, my solution is correct
If Francis drives 40 miles per hour. After 240 miles Francis' car breaks down then
40 x t = 240
t = 6 hours
Then Francis' car broke down by 3 pm.
Teneka reaches Francis car:
30 x t = 240
t = 8 hours
Then Teneka reaches Francis car by 5 pm
Which is answer D
If Francis drives 40 miles per hour. After 240 miles Francis' car breaks down then
40 x t = 240
t = 6 hours
Then Francis' car broke down by 3 pm.
Teneka reaches Francis car:
30 x t = 240
t = 8 hours
Then Teneka reaches Francis car by 5 pm
Which is answer D
